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yulyashka [42]
3 years ago
13

Fast really need help

Mathematics
2 answers:
IgorLugansk [536]3 years ago
8 0

Answer:

3^6 i think

Step-by-step explanation:

yanalaym [24]3 years ago
4 0

Answer:

Step-by-step explanation:

7)3^{2}*3^{4}=3^{2+4}=3^{6}\\\\8)\frac{4^{10}}{4^{2}}=4^{10-2}=4^{8}\\\\9)4^{3}*4^{-6}=4^{3-6}=4^{-3}=\frac{1}{4^{3}}

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Substitution Method<br>2x+5y=-1<br>y=3x+10​
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Substitution for both equations is (-3,1)
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Micaela bought for posters. A week later half of all her posters were lost during a move. There are now only 12 posters left. Ho
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andrezito [222]

Answer:

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Step-by-step explanation:

Not my answer Props to this guys: brainly.com/question/14438192

7 0
2 years ago
A hospital’s financial reimbursement payor mix indicates 35% of the patients have Medicare and 15% have Medicaid. Of those who h
Damm [24]

Using conditional probability, it is found that there is a 0.035 = 3.5% probability that a hospital patient has both Medicare and Medicaid.

<h3>What is Conditional Probability?</h3>
  • <em>Conditional probability</em> is the <u>probability of one event happening, considering a previous event</u>. The formula is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem, the events are:

  • Event A: Patient has Medicare.
  • Event B: Patient has Medicaid.

For the probabilities, we have that:

  • 35% of the patients have Medicare, hence P(A) = 0.35.
  • Of those who have Medicare, there is a 10% chance they also have Medicaid, hence P(B|A) = 0.1.

Then, applying the <em>conditional </em>probability:

P(B|A) = \frac{P(A \cap B)}{P(A)}

0.1 = \frac{P(A \cap B)}{0.35}

P(A \cap B) = 0.35(0.1)

P(A \cap B) = 0.035

0.035 = 3.5% probability that a hospital patient has both Medicare and Medicaid.

You can learn more about conditional probability at brainly.com/question/14398287

4 0
3 years ago
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