Answer:
The side length of each square is 2.12 units.
The length ad width of the rectangle are 2.12 and 4.24 units
Step-by-step explanation:
Let the width of the rectangle is x,
So, the length of the rectangle is 2x.
Area of the rectangle = 9 sq. units
[as area = length x width]
![\Rightarrow 9 = 2x^2](https://tex.z-dn.net/?f=%5CRightarrow%209%20%3D%202x%5E2)
![\Rightarrow x^2 = \frac{9}{2}=4.5](https://tex.z-dn.net/?f=%5CRightarrow%20x%5E2%20%3D%20%5Cfrac%7B9%7D%7B2%7D%3D4.5)
units
So, width of the rectangle, x= 2.12 units and
the llengthof the rectangle, 2x= 2 x 2.12= 4.24 units.
After division of the rectangle into two equal square, so, the area of each square will be half of the area of the rectangle.
The area of the rectangle = 9/2=4.5 square units.
Let a be the length of the sides of the square, so
Area ![= a^2](https://tex.z-dn.net/?f=%3D%20a%5E2)
![\Rightarrow a^2=4.5](https://tex.z-dn.net/?f=%5CRightarrow%20a%5E2%3D4.5)
![a = 1.5\sqrt{2}=2.121](https://tex.z-dn.net/?f=a%20%3D%201.5%5Csqrt%7B2%7D%3D2.121)
Hence, the side length of each square = 2.12 units.