Part 3: Write the equation of and graph an ellipse.
1 answer:
Answer:
Step-by-step explanation:
The center is halfway between vertices, at (4, -6).
It is also halfway between foci.
:::::
The vertices are vertically aligned, so the parabola is vertical.
General equation for a vertical ellipse:
(y-k)²/a² + (x-h)²/b² = 1
with
center (h,k)
vertices (h,k±a)
co-vertices (h±b,k)
foci (h,k±c), c² = a²-b²
Apply your data and solve for h, k, a, and b.
center (h,k) = (4, -6)
h = 4
k = -6
vertices (4,-6±a) = (4,-6±9)
a = 9
foci (4,-6±c) = (4,-6±5√2)
b² = a² - c² = 9² - (5√2)² = 31
b = √31
The equation becomes
(y+6)²/81 + (x-4)²/31 = 1
:::::
length of major axis = 2a = 18
length of minor axis = 2b = 2√31
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We have been given an expression . We are asked to find the solution to our given expression expressed as scientific notation.
Let us simplify our given expression.
Using exponent property , we will get:
Now to write our answer in scientific notation, we need our 1st multiple between 1 and 10. So we will rewrite our expression as:
Therefore, our required solution would be .
Answer:
c = 13.2
Step-by-step explanation:
* Lets explain how to solve the problem
- In Δ ABC
# Side a is opposite to ∠A
# Side b is opposite to ∠B
# Side c is opposite to ∠C
- The sine rule is:
#
* Lets solve the problem
- In Δ ABC
∵ m∠A = 16°
∵ m∠B = 49°
∵ The sum of the measures of the interior angles of a triangle is 180°
∴ m∠A + m∠B + m∠C = 180°
∴ 16° + 49° + m∠C = 180°
∴ 65° + m∠C = 180° ⇒ subtract 65° from both sides
∴ m∠C = 115°
- Lets use the sine rule to find c
∵ a = 4 and m∠A = 16°
∵ m∠C = 115°
∵
- By using cross multiplication
∴ c sin(16) = 4 sin(115) ⇒ divide both sides by sin(16)
∴
* c = 13.2