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astra-53 [7]
3 years ago
7

50 POINTS TO WHOEVER HELPS WITH THIS I NEED IT ASAP PLEASE HELP

Mathematics
1 answer:
Tresset [83]3 years ago
7 0

Answer:

<em>4a ) Difference ⇒ $ 63.24,</em>

<em>4b ) 4 children</em>

Step-by-step explanation:

4a ) If the number of children is represented by the value of x, let us substitute a family of 2 children as value of x into this equation we are given;

y = 21.08 * ( 2 ) + 85.15 ⇒ Multiply 21.08 by 2,

y = 42.16 + 85.15 ⇒ Combine like terms,

y = 127.31

If y ⇒ amount spent on grocery's, let us solve for the amount spent on 5 children, and subtract from this amount;

y = 21.08 * ( 5 ) + 85.15 ⇒ Multiply 21.08 by 5,

y = 105.4 + 85.15 ⇒ Combine like terms,

y = 190.55

Difference; 190.55 - 127.31 = 63.24,

<em>Solution; Difference ⇒ $ 63.24</em>

4b ) If the amount is $ 169.47, let us plug it into our given equation provided amount spent on groceries ⇒ y;

169.47 = 21.08x + 85.15 ⇒ Subtract 85.15 from either side of equation,

21.08x = 84.32 ⇒ Divide either side 21.08,

x = 4 children

<em>Solution; 4 children</em>

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The length of a diagonal of a quadrilateral shaped field Is 48 m And the length of perpendicular dropped on it from the remainin
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Step by step explanation:

Please find the attachment.    

We have been given that the length of a diagonal of a quadrilateral shaped field Is 48 m. The length of perpendicular dropped on it from the remaining apposite vertices are 16 m and 26 m.

We can see from our attachment that diagonal AC divides our quadrilateral field into two triangular fields and AC will be the base of both triangles.

To find the area of our given quadrilateral we will find the areas of both triangles and add the areas.

Let us find area of triangle ABC with base 48 m and height 26 m.

\text{Area of triangle}=\frac{1}{2}(\text{ Base}\times\text{ Height})

\text{Area of triangle ABC}=\frac{1}{2}\times 48\times 26  

\text{Area of triangle ABC}=24\times 26  

\text{Area of triangle ABC}=624

Therefore, the area of triangle ABC will be 624 square meters.

Now let us find area of triangle ADC with base 48 m and height 16 m.

\text{Area of triangle ADC}=\frac{1}{2}\times 48\times 16  

\text{Area of triangle ADC}=24\times 16  

\text{Area of triangle ADC}=384    

Therefore, the area of triangle ADC will be 384 square meters.

Now let us add areas of triangles ABC and ADC to get the area of our quadrilateral ABCD.

\text{Area of quadrilateral ABCD}=384+624  

\text{Area of quadrilateral ABCD}=1008  

Therefore, the area of quadrilateral shaped field will be 1008 square meters.



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