Answer: a. 1.981 < μ < 2.18
b. Yes.
Step-by-step explanation:
A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.
First, we calculate mean of the sample:


2.08
Now, we estimate standard deviation:


s = 0.1564
For t-score, we need to determine degree of freedom and
:
df = 12 - 1
df = 11
= 1 - 0.95
α = 0.05
0.025
Then, t-score is
= 2.201
The interval will be
± 
2.08 ± 
2.08 ± 0.099
The 95% two-sided CI on the mean is 1.981 < μ < 2.18.
B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.
4(x -2) +(y +5) = 0 . . . . . an equation
4x +y = 3 . . . . . . . . . . . . the equation in standard form
___
A graph can be seen at
https://www.desmos.com/calculator/3ct9gfxclj
Ur answer is 2% because u minus it and u find the percentage
There is a total of 9 spaces between the two.
Meaning that the " 5th" segment is the midpoint.
The answer is : ( 5, -1)
hope it helps you.
Answer:
The image is so blurred
Step-by-step explanation:
Please tell me all the measures used in your question or re ask your question and instead screen shot