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gregori [183]
3 years ago
10

What times something equals 26

Mathematics
2 answers:
ElenaW [278]3 years ago
8 0

13 multiplied by 2 is 26. Hope I helped
Lunna [17]3 years ago
3 0
6.5 times 4 and 13 times 2
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Can somebody help me ASAP. I attached a picture.
crimeas [40]

Answer:

½

Step-by-step explanation:

cot(2x) = 1/(tan(2x))

csc(x) = 1/(sin(x))

cot(2x)/csc(x) = sin(x)/tan(2x)

As x --> 0 this fraction is 0/0 which is an indeterminate form.

Using L'Hopital

Derivatives:

sin(x) ---> cos(x)

tan(2x) ---> 2sec²(2x)

cos(x)/(2sec²(2x))

= ½ as x --> 0

8 0
3 years ago
Find all the solutions in there interval (0,2pi) for cos5x=-1/2
oee [108]

Answer:

\frac{2\pi}{15},\frac{4\pi}{15},\frac{8\pi}{15},\frac{2\pi}{3},\frac{14\pi}{15}, \frac{16\pi}{15}, \frac{4\pi}{3},\frac{22\pi}{15}, \frac{26\pi}{15}, \frac{28\pi}{15}

Step-by-step explanation:

Solving trigonometric equations.

We are given a condition and we must find all angles who meet it in the provided interval. Our equation is

cos5x=-\frac{1}{2}

Solving for 5x:

5x=\frac{2\pi}{3}+2n\pi

5x=\frac{4\pi}{3}+2n\pi

The values for x will be

x=\frac{\frac{2\pi}{3}+2n\pi}{5}

x=\frac{\frac{4\pi}{3}+2n\pi}{5}

To find all the solutions, we'll give n values of 0, 1, 2,... until x stops belonging to the interval (0,2\pi)

For n=0

x=\frac{\frac{2\pi}{3}}{5}=\frac{2\pi}{15}

x=\frac{\frac{4\pi}{3}}{5}=\frac{4\pi}{15}

For n=1

x=\frac{\frac{2\pi}{3}+2\pi}{5}=\frac{8\pi}{15}

x=\frac{\frac{4\pi}{3}+2\pi}{5}=\frac{2\pi}{3}

For n=2

x=\frac{\frac{2\pi}{3}+4\pi}{5}=\frac{14\pi}{15}

x=\frac{\frac{4\pi}{3}+4\pi}{5}=\frac{16\pi}{15}

For n=3

x=\frac{\frac{2\pi}{3}+6\pi}{5}=\frac{4\pi}{3}

x=\frac{\frac{4\pi}{3}+6\pi}{5}=\frac{22\pi}{15}

For n=4

x=\frac{\frac{2\pi}{3}+8\pi}{5}=\frac{26\pi}{15}

x=\frac{\frac{4\pi}{3}+8\pi}{5}=\frac{28\pi}{15}

For n=5 we would find values such as  

x=\frac{\frac{2\pi}{3}+10\pi}{5}=\frac{32\pi}{15}

x=\frac{\frac{4\pi}{3}+10\pi}{5}=\frac{34\pi}{15}

which don't lie in the interval (0,2\pi)

The whole set of results is

\frac{2\pi}{15},\frac{4\pi}{15},\frac{8\pi}{15},\frac{2\pi}{3},\frac{14\pi}{15}, \frac{16\pi}{15}, \frac{4\pi}{3},\frac{22\pi}{15}, \frac{26\pi}{15}, \frac{28\pi}{15}

6 0
4 years ago
Why might you complete a 1040 instead of a 1040EZ?
Katyanochek1 [597]
<span>Your taxable income must be less than $100,000 and only come in the form of wages</span>
6 0
4 years ago
<img src="https://tex.z-dn.net/?f=%5Cboxed%7B%5Cblue%7B%5Cmathscr%7BHello%5C%3ABrainliacs%7D%7D%7D" id="TexFormula1" title="\box
andrew-mc [135]

For the reaction,

CO(g) + H_2 O(g) = CO_2(g) + H_2(g)

Initial concentration:

<u>0.1M</u> , <u>0.1M</u> , <u>0</u> , <u>0</u>

Let 'x' mole per litre of each of theproduct be formed.

At equilibrium:

<u>(0.1 – x)M</u> , <u>(0.1 – x)M</u> , <u>xM</u> , <u>xM</u>

where x is the amount of Carbon dioxide and Hydrogen, at equilibrium.

Hence, equilibrium constant can be written as,

K_c = \frac{x²}{(0.1 – x)²} = 4.24

→ x² = 4.24 (0.01 + x² – 0.2x)

→ x² = 0.0424 + 4.24 x² - 0.848x

→ 3.24x² - 0.848x + 0.0424 = 0

<em>a = 3.24, b = -0.848, c = 0.0424</em>

(for quadratic equation ax² + bx+c=0)

x =  \frac{( - b \: ± \: \sqrt{ {b}^{2} - 4ac) } }{2a}

=  > x =  \frac{ - ( - 0.848 \: ± \:  \sqrt{( - 0.848)^{2} - 4(3.24)(0.0424) } }{2 \times 3.24}

=  > x =  \frac{ - 0.848±0.4118}{6.48}

x_1 =  \frac{0.848 - 0.4118}{6.48} = 0.067

x_2 =  \frac{0.848 + 0.4118}{6.48} = 0.194

Here, the value 0.194 should be neglected because it will give concentration of the reactant which is more than initial concentration.

∴ The equilibrium concentrations are :-

[CO_2] [H_2] = x = 0.067M

[CO] [H_2 O] = 0.1 - 0.067 = 0.033M

7 0
3 years ago
Adam uses coconut milk for the dessert.
dmitriy555 [2]
V=(π)(r^2)(h)

π=3
r=half of the diameter=4
h=12

V=(3)(4^2)(12)
    = (3)(16)(12)
        = 576 cm cubed 


4 0
3 years ago
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