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Rashid [163]
3 years ago
10

In STU, the measure of

Mathematics
1 answer:
snow_lady [41]3 years ago
3 0

Answer:

x=51.9

Step-by-step explanation:

sin x = 7.4/9.4

sin x= 0.787

sin^-1(0.787)=x

x=51.9

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Answer:

Step-by-step explanation:

term            | Phrase

inequality   | 63<8k

Expression | bc+1-(8d-4)

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7 0
3 years ago
Read 2 more answers
Look at the problems 2.3×3.68 and 23×368. How are they similar? Which problem has a greater product?
Margarita [4]

Here is your answer:

1. These equations are similar because they "both share the same numbers but one is a decimal and the other is a whole number."

2. You have to solve each equation in order to determine which number is greater:

  • 2.3\times 3.68
  • 2.3 \times 3.68 = 8.464
  • = 8.464

And:

  • 23 \times 368 =
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  • = 8464

Finally:

  • 8.464 < 8464

Therefore "8,464 is greater than 8.464."

Hope this helps!

3 0
3 years ago
Round 2.85 to the nearest hunderdth
andreyandreev [35.5K]
Answer 2.85

On rounding to nearest hundredths, we get than 2.85 as at thousandths place, there is 9 which is greater than 5, so 1 is added to the hundredth value.
3 0
3 years ago
Use the graph to write a linear function that relates y to x.
allsm [11]

Answer:

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Step-by-step explanation:

6 0
3 years ago
The coordinates of the vertices of a regular polygon are given. Find the area of the polygon to the nearest tenth.
alexandr1967 [171]

Answer:

The area is equal to 8\ units^{2}

Step-by-step explanation:

we have

A(0, 0), B(2, -2), C(0, -4), D(-2, -2)

Plot the figure

The figure is a square (remember that a regular polygon has equal sides and equal internal angles)

see the attached figure

The area of the square is

A=AB^{2}

<u><em>Find the distance AB</em></u>

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute the values

AB=\sqrt{(-2-0)^{2}+(2-0)^{2}}

AB=\sqrt{(-2)^{2}+(2)^{2}}

AB=\sqrt{8}

AB=2\sqrt{2}\ units

<u><em>Find the area of the square</em></u>

A=(2\sqrt{2})^{2}

A=8\ units^{2}

4 0
3 years ago
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