Your perimeter of a 5 sided shape is a+b+c+d+e= P (P for perimeter)
add all of your sides of that shape together to get your perimeter
if you post your question i can help..
hope this helps
Answer:
<h2>3(2+4)÷(10-1) = 2</h2><h2 />
Step-by-step explanation:
3×(2+4)÷(10-1) = 3×(6)÷(9) = 18÷9 = 2
The answer it 1. is A.
The answer to 2. is B.
Answer:
We have been given an equation ![x^2+9x+20=0](https://tex.z-dn.net/?f=x%5E2%2B9x%2B20%3D0)
We will factorize it by middle term splitting.
Step 1: ![x^2+5x+4x+20=0](https://tex.z-dn.net/?f=x%5E2%2B5x%2B4x%2B20%3D0)
Taking common factors out by clubing first two terms ad last two terms
Step 2: ![x(x+5)+4(x+5)=0](https://tex.z-dn.net/?f=x%28x%2B5%29%2B4%28x%2B5%29%3D0)
Step 3: ![(x+4)(x+5)=0](https://tex.z-dn.net/?f=%28x%2B4%29%28x%2B5%29%3D0)
Equating both above factors to zero as:
Step 4: ![(x+4)=0\Rightarrow x=-4](https://tex.z-dn.net/?f=%28x%2B4%29%3D0%5CRightarrow%20x%3D-4)
And
.
Answer:
The answer is first option i.e
![\triangle ABC \cong \triangle GHJ\ \textrm{angle - side - angle test i.e ASA}\\](https://tex.z-dn.net/?f=%5Ctriangle%20ABC%20%5Ccong%20%5Ctriangle%20GHJ%5C%20%5Ctextrm%7Bangle%20-%20side%20-%20angle%20test%20i.e%20ASA%7D%5C%5C)
Step-by-step explanation:
Given:
1. angle ABC = angle GHJ
2. BC = HJ
3. angle BCA = angle HJG
Proof:
In ΔABC and ΔGHJ
![\angle ABC \cong \angle GHJ \ Given\\BC \cong HJ\ \textrm{Given}\\\angle BCA \cong \angle HJG \ \textrm{Given}\\\\\triangle ABC \cong \triangle GHJ\ \textrm{angle - side - angle test i.e ASA}\\](https://tex.z-dn.net/?f=%5Cangle%20ABC%20%5Ccong%20%5Cangle%20GHJ%20%5C%20Given%5C%5CBC%20%5Ccong%20HJ%5C%20%5Ctextrm%7BGiven%7D%5C%5C%5Cangle%20BCA%20%5Ccong%20%5Cangle%20HJG%20%5C%20%5Ctextrm%7BGiven%7D%5C%5C%5C%5C%5Ctriangle%20ABC%20%5Ccong%20%5Ctriangle%20GHJ%5C%20%5Ctextrm%7Bangle%20-%20side%20-%20angle%20test%20i.e%20ASA%7D%5C%5C)
Hence proved