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3 years ago

Need help with this trigonometry

Mathematics

1 answer:

Vlad1618 [11]3 years ago

8 0

X=6 y and z are both 30 degrees

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Whats equivalent to 11 to the 8th power over 11 to the 3rd power

arsen [322]

I did it wrong the first time you're answer is b. 11*11^4

3 0

3 years ago

Suppose that the sitting back-to-knee length for a group of adults has a normal distribution with a mean of mu equals 24.4 in.

solong [7]

Answer:

$P(X \geq 26.6) = 0.0336$ , which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 24.4, \sigma = 1.2$

In this problem, a value x is significantly high if:

$P(X \geq x) = 0.01$

Using these criteria, is a back-to-knee length of 26.6 in. significantly high?

We have to find the probability of the length being 26.6 in or more, which is 1 subtracted by the pvalue of Z when X = 26.6. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{26.6 - 24.4}{1.2}$

$Z = 1.83$

$Z = 1.83$ has a pvalue of 0.9664.

1 - 0.9664 = 0.0336

$P(X \geq 26.6) = 0.0336$ , which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

6 0

3 years ago

What value(s) of x will make x^2=25 true

lora16 [44]

Answer:

5 and up

Step-by-step explanation:

5^2=25

thus

25=25

5 0

3 years ago

BYU QUESTION GEOMETERY HELP(photo)I don't know

Tatiana [17]

A fellow BYU courser I see.

Now, I am in the same course as you, but shouldn't there be a "None of the Above" option? (I only finished 1.1 so I don't really know.) I think that is correct.

Based on the picture (I know the picture is almost never drawn to scale but still) I think these line segments aren't parallel.

Also, I think the actual proof involves the Alternate Exterior Angles theorem, and those angles in this case are angles ∠BFC and ∠FCE which aren't listed.

7 0

3 years ago

A machine in a candy company creates 9,328 pieces of candy each hour. if a box holds 98 pieces of candy, how many boxes can be f

Helen [10]

Answer:

Step-by-step explanation:

9,328 and you would divide that by 98 and the answer would be 95.18367347 boxes

4 0

2 years ago