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trapecia [35]
3 years ago
15

Helppppppppppppppppppppppp

Mathematics
1 answer:
Artist 52 [7]3 years ago
7 0

Answer: Its A or B

Step-by-step explanation:

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Please help its due tonight!!
Lynna [10]

Answer:

your really think ik the answer

Step-by-step explanation:

yea the  sorry

8 0
3 years ago
Read 2 more answers
I really need help with this question!
ololo11 [35]
Same as all the other ones like this.

Since the two figures are similar . . .

-- The ratio of of their volumes is  R³ .

-- The ratio of their surface areas is  R² .

-- The ratio of their dimensions is  R .

So  R³  is        729 / 2744 .

Take the cube root of that and you'll have  R .

Then square R and you'll have the ratio of their surface areas.
5 0
3 years ago
Why does it take 3 copies of 1/6 to show the same amount as 1 copy of 1/2?
melisa1 [442]
Because 1/2 of 6 =1/3 and 1/2×1/3=1/6
7 0
3 years ago
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HELP PLEASE! ASAP ! <br> These 2 questions !
Vlad1618 [11]

Answer: 9 is true, 10 is false

Step-by-step explanation:

The key to these problems is to make sure the sequence of the letters is equal: 10 would be correct if they said DF ≅XZ

3 0
2 years ago
If a = √3-√11 and b = 1 /a, then find a² - b²​
Serga [27]

If b=\frac1a, then by rationalizing the denominator we can rewrite

b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8

Now,

a^2 - b^2 = (a-b) (a+b)

and

a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8

a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8

\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}

5 0
2 years ago
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