1. Expand
6x + a = 5x + 5t
2. Get x on one side
6x - 5x = 5t - a
3. Simplify
x = 5t - a (I think)
Answer:
4/3 (= 1 1/3)
Step-by-step explanation:
2/3 - (-2/3)
= 2/3 + 2/3
= (2+2) / 3
= 4/3
= 1 1/3
Answer:
31.5 squared cm
Step-by-step explanation:
Let's start with the triangle part :)
We have a base half a base of 3, so let's add 3 more to make it complete, which gives us 6.
6cm (base) x 6 cm (height) = 36 cm.
Since it's a triangle, we must divide by 2 which gives us 18 cm.
Now let's move on to the circle.
we have a radius of 3.
in order to find area of a circle, we have to do pi x r squared.
We have a radius of 3 so let's square it, which give us 9. after that we multiply 9 by pi.
In the directions, it says use 3 for pi. So we do
3 x 9 which equals 27.
But WAIT- it's a <u>half</u> circle so we <u>divide 27 by 2</u> which gives us <u>13.5 </u><u>cm.</u>
Let's add the two
<u>1</u><u>8</u><u> </u><u>cm </u><u>+</u><u> </u><u>1</u><u>3</u><u>.</u><u>5</u><u> </u><u>cm</u> <u>=</u><u> </u><u> </u><u>3</u><u>1</u><u>.</u><u>5</u><u> </u><u>cm </u><u>squared</u> <u>(</u><u>remember</u><u> </u><u>to </u><u>square </u><u>it </u><u>since </u><u>it's </u><u>area!</u><u>!</u><u>)</u>
<u>I </u><u>hope </u><u>this </u><u>helped!</u><u>!</u><u>!</u><u> </u><u><</u><u>3</u>
Answer:
Draw a perpendicular line from point A to line segment BC. Name the intersection of said line at BC “E.” You now have a right angled triangle AED.
Now, you know AD = 6 m. Next, given that the trapezoid is a normal one, you know that the midpoints of AB and DC coincide. Therefore, you can find the length of DE like so, DE = (20–14)/2 = 3 m.
Next, we will use the cosign trigonometric function. We know, cos() = adjacent / hypotenuse. Hence, cosx = 3/6 = 1/2. Looking it up on a trigonometric table we know, cos(60 degrees) = 1/2. Therefore, x = 60 degrees.
Alternatively, you could simply use the Theorem for normal trapezoids that states that the base angles will be 60 degrees. Hope this helps!