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chubhunter [2.5K]
3 years ago
6

Two cars are travelling from Toronto to Quebec. Car A left Toronto at 8 a.m. and is moving with an average speed of 70 km/h. Car

B left Toronto at 10 a.m. and its average speed is 90 km/h. How many hours will it take for car B to catch car A?
(please show all your work Let, So, Equation and Solution and Therefore Statement)
Mathematics
1 answer:
vodka [1.7K]3 years ago
7 0

Answer:

It'll take 7 hours for the car B to cath up to A

Step-by-step explanation:

In order to solve this problem we can write the equation from the distance of each car. Assuming that t = 0 happens when the second car leaves Toronto. When the second car leaves Toronto, the first one is on the road for two hours already, thefeore it travelled a total of:

distance = speed*time = 70*2 = 140

We have:

Car A:

x(t) = 70*t + 140

Car B:

x(t) = 90*t

We now need to find the value of "t" that makes x(t) the same for both cars:

90*t = 70*t + 140

20*t = 140

t = 140 / 20 = 7 h

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Step-by-step explanation:

Calculation:

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Find three different ratios that are equivalent to ratio 3 : 11
Mnenie [13.5K]

Answer:

6:22

9:33

12:44

Step-by-step explanation:

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Multiplying by 2,

6:22

Multiplying by 3

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Multiplying by 4

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Please help me with this!!<br> Thank u
topjm [15]

Answer:

Step-by-step explanation:

Left

When a square = a linear, always expand the squared expression.

x^2 - 2x + 1 = 3x - 5                Subtract 3x from both sides

x^2 - 2x - 3x + 1 = -5

x^2 - 5x +1 = - 5                      Add 5 to both sides

x^2 - 5x + 1 + 5 = -5 + 5

x^2 - 5x + 6 = 0

This factors

(x - 2)(x - 3)

So one solution is x = 2 and the other is x = 3

Second from the Left

i = sqrt(-1)

i^2 = - 1

i^4 = (i^2)(i^2)

i^4 = - 1 * -1

i^4 = 1

16(i^4) - 8(i^2) + 4

16(1) - 8(-1) + 4

16 + 8 + 4

28

Second from the Right

This one is rather long. I'll get you the equations, you can solve for a and b. Maybe not as long as I think.

12 = 8a + b

<u>17 = 12a + b         Subtract</u>

-5 = - 4a

a = - 5/-4 = 1.25

12 = 8*1.25 + b

12 = 10 + b

b = 12 - 10

b = 2

Now they want a + b

a + b = 1.25 + 2 = 3.25

Right

One of the ways to do this is to take out the common factor. You could also expand the square and remove the brackets of (2x - 2). Both will give you the same answer. I think expansion might be easier for you to understand, but the common factor method is shorter.

(2x - 2)^2 = 4x^2 - 8x + 4

4x^2 - 8x + 4 - 2x + 2

4x^2 - 10x + 6    The problem is factoring since neither of the first two equations work.

(2x - 2)(2x - 3)     This is correct.

So the answer is D

5 0
3 years ago
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