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masha68 [24]
2 years ago
14

What is the best estimate for 56.23 - 45.9? A. 9 B. 10 C. 11 D. 15

Mathematics
1 answer:
DIA [1.3K]2 years ago
5 0

Answer:

10 Letter B

Step-by-step explanation:

56.23 rounds down to 56 and 45.9 rounds up to 46. So 56 - 46 = 10

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The rectangle shown represents the base of a cracker box shaped like a rectangular prism. Use the ruler provided to measure the
malfutka [58]

There is no rectangle shown, nor ruler given to measure and attempt your work. Nevertheless, I will illustrate how to find the volume of a rectangular prism.

Step-by-step explanation:

Given a rectangular prism of sides

Length = l

Width = w

Height = h

The volume of this prism is given as

V = l × b × h.

Example, if

Length = 4cm

Width = 3cm

Height = 2cm

Volume = 4 × 3 × 2

= 24cm³.

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2 years ago
That's not an answer for me
Alik [6]

Answer:

so you need a answer or a question

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3 years ago
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You earned $204 from your job last week. You have two relatives with birthdays coming up and you want to
horrorfan [7]

Answer: $62

Step-by-step explanation:

From the question, we are informed that someone earned $204 from a job last week and has two relatives with birthdays coming up and wants to

spend the same amount on each of them but still wants to have $80 left.

To calculate the amount of gift spent on each, we have to deduct $80 from $204 firstly. This will be:

= $204 - $80

= $124

This means that the person will spend $124 on both of them, then we divide $124 by 2. This will be:

= $124/2

= $62

The amount spent on each gift will be $62.

7 0
3 years ago
Find the solution of the given initial value problem. ty' + 2y = sin t, y π 2 = 9, t > 0 y(t) =
Helen [10]

For the ODE

ty'+2y=\sin t

multiply both sides by <em>t</em> so that the left side can be condensed into the derivative of a product:

t^2y'+2ty=t\sin t

\implies(t^2y)'=t\sin t

Integrate both sides with respect to <em>t</em> :

t^2y=\displaystyle\int t\sin t\,\mathrm dt=\sin t-t\cos t+C

Divide both sides by t^2 to solve for <em>y</em> :

y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac C{t^2}

Now use the initial condition to solve for <em>C</em> :

y\left(\dfrac\pi2\right)=9\implies9=\dfrac{\sin\frac\pi2}{\frac{\pi^2}4}-\dfrac{\cos\frac\pi2}{\frac\pi2}+\dfrac C{\frac{\pi^2}4}

\implies9=\dfrac4{\pi^2}(1+C)

\implies C=\dfrac{9\pi^2}4-1

So the particular solution to the IVP is

y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac{\frac{9\pi^2}4-1}{t^2}

or

y(t)=\dfrac{4\sin t-4t\cos t+9\pi^2-4}{4t^2}

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2 years ago
Determine the cube root of 64x125<br> The cube root of those numbers
andrey2020 [161]
The cube root of 64x125 is 500
4 0
3 years ago
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