Answer:
11,7,-3 respectively
Step-by-step explanation:
when x is -2 ,0 and 5 the result will be 11, 7 and -3 respectively
Answer:
Step-by-step explanation:
Answer:

Step-by-step explanation:
Let's start by using change of base property:

So, for 

Now, using change of base for 

You can express
as:

Using reduction of power property:


Therefore:

As you can see the only difference between (1) and (2) is the coefficient
:
So:


Ok , with that information we can write the equations
x + y = 6
5x + 4y = 28
Where x = how many people ordered chicken
and y = how many people ordered egg salad
Through elimination , we can set one of the variables in both equations equal so we can eliminate it :
(4)x + (4)y = (4)6
5x + 4y = 28
4x + 4y = 24. equation 1
5x + 4y = 28. equation 2
Now we can subtract the second equation by the first equation and isolate one variable:
equation 2 - equation 1
5x - 4x + 4y - 4y = 28 - 24
x = 4
Now that we discovered our x value ( How many people ordered chicken salad ) , we can apply it to one of the equations and discover y ( how many people ordered egg salad)
x + y = 6
x= 4
4 + y = 6
We can shift 4 to the other side of the equation by subtracting 4 from both sides of the equation:
4 - 4 + y = 6 - 4
y = 2
x=4 and y=2
So the awnser is :
4 people ordered chicken salad and 2 people ordered egg salad!
I hope you understood my brief explanation!!
p.s if you want to know how to use another method to solve these problems ( Substition) , just let me know in a comentary down here
Using law of cosines:
Cos(angle) = adjacent/ hypotenuse
Cos(22) = 12/x
Rewrite to get:
X = 12/cos(22)
Simplify:
X = 12.9424
Round the answer as needed.