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rosijanka [135]
3 years ago
13

Given sets A and B, prove that the following two conditions are equivalent: (1) A \ B = B \ A, (2) A = B.

Mathematics
1 answer:
Jet001 [13]3 years ago
7 0

Answer:

See proof below

Step-by-step explanation:

Remember that if we want to prove that two propositions P and Q are equivalent, we have to prove that P implies Q and Q implies P.

(1)→(2) Suppose that A \ B = B \ A, we will prove that A = B. Let x∈A, and for the sake of a contradiction suppose that x∉B. Then x∈A \ B by definition of difference of sets. Since A \ B = B \ A and x∈A \ B then x∈B \A, that is, x∈B and x∉A, which is a contradiction to the first assumption regarding x. Therefore x∈B, for all x∈A, which implies that A⊆B.

We can use a similar argument to prove that B⊆A, and both inclusions imply that A=B as we wanted to prove. Indeed, let x∈B, and suppose that x∉A Thus x∈B \ A. But A \ B = B \ A, then  x∈A \B, that is, x∈A and x∉B, which is absurd. Then x∈A, for all x∈B, that is, B⊆A.  

(2)→(1). Suppose that A = B. We will prove that A \ B = B \ A. By definition,  A \ B is the set of elements of A that do not belong to B. However, A=B, so A \ B is the set of elements of A that do not belon to A. There no exists such an element, since this condition is contradictory, thus A \ B=∅, the empty set. Similarly, B \ A = B \ B = ∅. The empty set is unique, therefore A \ B=∅=  B \ A.

The previous parts show that (1) and (2) are logically equivalent.

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Answer:

see explanation

Step-by-step explanation:

note when x = - 3

(- 3)³ + 2(- 3)² + 4(- 3) + 21 = - 27 + 18 - 12 + 21 = 0

hence x = - 3 is a zero and (x + 3) is a factor and dividing gives

\frac{x^3+2x^2+4x+21}{x+3} = (x + 3)(x² - x + 7)

For zeros equate to zero

(x + 3)(x² - x + 7) = 0

equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

x² - x + 7 = 0 ← solve using quadratic formula

x = (1 ± \sqrt{1-28} ) / 2 = (1 ± 3i\sqrt{3} ) / 2

x = \frac{1}{2} ± \frac{3i\sqrt{3} }{2}

zeros are x = - 3, x = \frac{1}{2} ±\frac{3i\sqrt{3} }{2}


5 0
3 years ago
Every month Jordan puts $14 into her bank account. Her grandma puts additional money into Jordan's bank account every month. Aft
vesna_86 [32]

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8 0
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Math help guys how wouls i work this out
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x < 6

You can graph your answer by drawing an open circle at the 6 and coloring the line to the left. The circle should be open, because x is <em>less than 6</em>, not less than or equal to. You would color to the left to show that x can be anything less than 6.

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Choices:<br><br> One-sixth cups<br> Five-sixths cups<br> 1 and two-thirds cups<br> 1 and 5 / 6 cups
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Answer:

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Step-by-step explanation:

Patel needs the orange juice for his family = 3 cups

He needs more orange juice = 3 cups - Sum of juice squeezed from different oranges

=3-(\frac{13}{15}+\frac{1}{5}+\frac{9}{20}+\frac{5}{11}+\frac{7}{15})

L.C.M. of the denominators = 660

=3-\frac{572+132+297+300+308}{660}

=3-\frac{1609}{660}

= \frac{1980-1609}{660}

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