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madam [21]
3 years ago
13

Quadrilateral ABCD is translated up and to the right and then rotated about point Q. Which congruency statement is correct?

Mathematics
1 answer:
valentina_108 [34]3 years ago
9 0

Answer:ABCD = ZYXW

Step-by-step explanation:

ABCD = WXYZ

ABCD = ZYXW

ABCD WZYX

ABCD = ZWXY

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subtract 60k (that is the 15 years multiplied by 4k) from 450k and you get 390k.

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WILL MARK BRAINLIEST!!! Find the fifth roots of 243(cos 240° + i sin 240°).
Snowcat [4.5K]

Answer:

<h2>3(cos 336 + i sin 336)</h2>

Step-by-step explanation:

Fifth root of 243 = 3,

Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),

then r^5( cos  Ф  + i sin  Ф )^5 = 243(cos 240 + i sin 240).

Equating equal parts and using de Moivre's theorem:

r^5 =243  and  cos  5Ф  + i sin  5Ф = cos 240 + i sin 240

r = 3 and  5Ф = 240 +360p so Ф =  48 + 72p

So Ф = 48, 120, 192, 264, 336  for   48 ≤ Ф < 360

So there are 5 distinct solutions given by:

3(cos 48 + i sin 48),

3(cos 120 + i sin 120),

3(cos 192 + i sin 192),

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6 0
3 years ago
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irina1246 [14]

Answer:

x = -3 + 2\sqrt2  \ , \ x = -3 - 2\sqrt2

Step-by-step explanation:

x² + 6x + 1 = 0

a = 1 , b = 6 , c = 1

x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\x = \frac{-6 \pm \sqrt{36-4}}{2}\\\\x=\frac{-6 \pm \sqrt{32}}{2}\\\\x= \frac{-6 \pm \sqrt{16 \times 2}}{2}\\\\x = \frac{-6 +4\sqrt2 }{2}\\\\x = -3 + 2\sqrt2  \ , \ x = -3 - 2\sqrt2

7 0
3 years ago
Read 2 more answers
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