The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)
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on what interval is the function positive?</h3>
The function is positive when g(x) > 0.
Then we need to solve:
∛(x - 3) > 0
We can directly remove the cubic root, because it does not affect the sign of the argument, then:
x - 3 > 0
x > 3
The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)
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Answer:
Step-by-step explanation:
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Answer:
4.45935
Step-by-step explanation:
\frac{d}{dx}\left(\frac{1+x^4+x^6}{x^2+x+1}\right)=\frac{4x^7+5x^6+8x^5+3x^4+4x^3-2x-1}{\left(x^2+x+1\right)^2}
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Answer:
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