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Debora [2.8K]
2 years ago
12

Given g of x equals cube root of the quantity x minus 3, on what interval is the function positive?

Mathematics
2 answers:
Neporo4naja [7]2 years ago
8 0

The interval which the function is positive is (3, ∝)

<h3>How to determine the positive interval?</h3>

The equation of the function is given as:

g(x) =∛x - 3

Set the radical greater than 0

x - 3 > 0

Add 3 to both sides of the inequality

x > 3

Express as an interval notation

(3, ∝)

Hence, the interval which the function is positive is (3, ∝)

Read more about function interval at:

brainly.com/question/1600302

#SPJ1

zmey [24]2 years ago
5 0

The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)

<h3>on what interval is the function positive?</h3>

The function is positive when g(x) > 0.

Then we need to solve:

∛(x - 3) > 0

We can directly remove the cubic root, because it does not affect the sign of the argument, then:

x - 3 > 0

x > 3

The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)

If you want to learn more about functions:

brainly.com/question/2456547

#SPJ1

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Suppose f⃗ (x,y,z)=⟨x,y,4z⟩f→(x,y,z)=⟨x,y,4z⟩. let w be the solid bounded by the paraboloid z=x2+y 2 z=x2+y2 and the plane z=9.z
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