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1 year ago

Given g of x equals cube root of the quantity x minus 3, on what interval is the function positive?

Mathematics

2 answers:

Neporo4naja [7]1 year ago

8 0

The interval which the function is positive is (3, ∝)

<h3>How to determine the positive interval?</h3>

The equation of the function is given as:

g(x) =∛x - 3

Set the radical greater than 0

x - 3 > 0

Add 3 to both sides of the inequality

x > 3

Express as an interval notation

(3, ∝)

Hence, the interval which the function is positive is (3, ∝)

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zmey [24]1 year ago

5 0

The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)

<h3>on what interval is the function positive?</h3>

The function is positive when g(x) > 0.

Then we need to solve:

∛(x - 3) > 0

We can directly remove the cubic root, because it does not affect the sign of the argument, then:

x - 3 > 0

x > 3

The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)

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What divides a two dimensional shape into two congruent shapes

zaharov [31]

Answer:

Rectangle is a 2dimensional shape so, let me explain using it

The diagonal of a rectangle divides the rectangle into two triangles that are congruent and they are the same size and shape.

Another example is parallelogram

The diagonal of a parallelogram also divides the figure into two triangles that are congruent.

Step-by-step explanation:

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3 years ago

If the equations 2x +y =7 and x-y=2are solved simultaneously, then y=_________

alisha [4.7K]

Answer:

y = -2x + 7 and y = x - 2

Step-by-step explanation:

2x + y = 7

y = -2x +7

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2 years ago

For each given p, let ???? have a binomial distribution with parameters p and ????. Suppose that ???? is itself binomially distr

pshichka [43]

Answer:

See the proof below.

Step-by-step explanation:

Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."

Solution to the problem

For this case we can assume that we have N independent variables $X_i$ with the following distribution:

$X_i Bin (1,p) = Be(p)$ bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this:

$Z = \sum_{i=1}^N X_i$

From the info given we know that $N \sim Bin (M,q)$

We need to proof that $Z \sim Bin (M, pq)$ by the definition of binomial random variable then we need to show that:

$E(Z) = Mpq$

$Var (Z) = Mpq(1-pq)$

The deduction is based on the definition of independent random variables, we can do this:

$E(Z) = E(N) E(X) = Mq (p)= Mpq$

And for the variance of Z we can do this:

$Var(Z)_ = E(N) Var(X) + Var (N) [E(X)]^2$

$Var(Z) =Mpq [p(1-p)] + Mq(1-q) p^2$

And if we take common factor $Mpq$ we got:

$Var(Z) =Mpq [(1-p) + (1-q)p]= Mpq[1-p +p-pq]= Mpq[1-pq]$

And as we can see then we can conclude that $Z \sim Bin (M, pq)$

8 0

3 years ago

Warren, a golf fan, was curious about how often professional golfers make successful putts from various distances. He looked at

anzhelika [568]

Answer:

Explained below.

Step-by-step explanation:

A correlation coefficient is a mathematical measure of certain kind of correlation, in sense a statistical relationship amid two variables

Negative correlation is a relationship amid two variables in which one variable rises as the other falls, and vice versa.

Values amid 0.7 and 1.0 (-0.7 and -1.0) implies a strong positive (negative) linear relationship amid the variables.

It is provided that Warren noticed a strong negative linear relationship between the success rate and putt distances.

This implies that as the putt distances are increasing the success rates are decreasing and as the putt distances are decreasing the success rates are increasing.

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2 years ago

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kotykmax [81]

Answer:

All points on line x+y = 0 or x-y=0 will satisfy the transformation.

Step-by-step explanation:

Let (x, y) be the general such point.

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All points on line x+y = 0 or x-y=0 will satisfy the transformation.

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2 years ago