Meteorites remains are most commonly found in Antarctica. The reason for this is because of the fact that Antarctica is covered in snow and ice. In such conditions black meteorites are easier to spot and retrieve than <span>finding them in a camouflage environment or urban area. </span>
Answer:
GGC-UAA
Explanation:
C bind with G, T bind with A, Thymine is not present in mRna so U will bind with A
Answer:
In meiosis I there is prophase I, metaphase I, anaphase I, and telophase I and then in meiosis II there is prophase II, metaphase II, anaphase II, and telophase II.
Explanation:
In meiosis I we have;
Prophase I in which a pair of homologous chromosomes line up and form a tetrad. This is the stage during which genetic recombination occurs.
Metaphase I occurs, during which the homologous chromosomes line up opposite each other at the metaphase plate. The chromosomes orientate themselves randomly, thus homologous chromosomes are distributed randomly to daughter cells .
In Anaphase I, homologous chromosomes move to opposite sides of the cells but sister chromatids remain together. Each cell now has 23 chromosomes.
Telophase I in which the homologous chromosomes move to the poles and cytokinesis occurs. Two daughter cells are formed.
In meiosis II we have;
Prophase II (note: there is no interphase as seen in mitosis) during which chromosomes start to move to the metaphase II plate. There is no replication.
Next is metaphase II when the chromosomes align at the metaphase II plate.
In anaphase II the sister chromatids separate from each other and move towards opposite poles.
Lastly, in telophase II cytokinesis occurs again and four daughter cells are produced. Each of the four daughter cells has 23 chromosomes.
They show which parts of the brain are involved in specific activities.
Answer:
e) phosphorylation to phosphoenolpyruvate
Explanation:
phosphoenol pyruvate is not the fate of the pyruvate . pyruvate can convert into the phosphoenole pyruvate in the reverse of the glycolysis which will utilize the ATP . So , this can not be the fate of pyruvate because in the breakdown of the glucose through glycolysis pyruvate is the end product and phosphoenol pyruvate is the intermediate .
