The true statements are:
- Substrate level phosphorylation ocvurs during Pyruvate oxidation
- 32 ATP molecules can be made by cellular respiration but only 2 ATP molecules when oxygen is lacking
- Electrons move from protein to protein due to increasing electronegativity in the electron transport chain
- ADP is phosphorylated in the matrix of the mitochondria during oxidative phosphorylation
- ATP inhibits pyruvate dehydrogenase by feedback inhibition
<h3>What is glucose oxidation?</h3>
Glucose oxidation refers to the process in the cells in which glucose molecules are oxidized to form ATP and carbon dioxide in the presence of oxygen.
The first stage of glucose oxidation is the conversion to pyruvate.
Pyruvate is oxidized to acetylCoA.
AcetylCoA enters the citric acid cycle to produce reducing equivalents, NADH for the electron transport chain.
- The true statements about pyruvate oxidation is that there is substrate level phosphorylation during the process
- When there is sufficient oxygen, 36 ATP molecules can be made (theoretically) by cellular respiration. However, when oxygen is lacking, only 2 ATP molecules are made.
- In the electron transport chain of cellular respiration, electrons move from protein to protein due to increasing electronegativity
- During oxidative phosphorylation, ADP is phosphorylated in the matrix of the mitochondria
- Aerobic respiration can be regulated by feedback inhibition of pyruvate dehydrogenase by ATP.
Learn more about pyruvate oxidation at: brainly.com/question/22565849
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<span> Basically the male will have CC, the hen will have cc, and neither of them will have I. The key thing is that _all_ the chicks are coloured.
The male must have at least 1 C to be coloured, and cannot possess the dominant I. The hen has cc and/or an I to not be coloured.
That one chick is coloured would tell you little - only that the hen couldn't have 2 inhibitor alleles because otherwise the chick would have to have one and it doesn't.
However, for all of many chicks to be coloured, that means that the hen can't have any inhibitor alleles (otherwise around 50% would be white for that reason alone).
So to be colourless, the hen must be cc. However, if the male had only 1 colour allele (ie it was Cc) that would still mean that 50% of the chicks would be Cc (daddy's 'c' and one of mummy's 'c's).
Hope this helps please award brainly :)
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Answer:
patient care – dietitians in hospitals and nursing homes educate patients and family members on eating well. They work with them to make sure that diets meet individual needs. They develop menus to meet patients' nutritional needs.
Explanation:
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I think it is compound, that is a I think so I might be wrong
It is a case of CODOMINANCE where the two alleles are expressed
