Hello :
let : z = 4-3ii z' = -2+7i
the distance between the points 4-3i and -2+7i is : <span>|z - z' |
</span> |z - z' | = |4-3i+2-7i| = |6-10i | =√(6²+(-10)²) =√136
7x+y-9=0
move constant to the left by adding its opposite to both sides. the sum of the two =0
Answer:
EG = 16 and FH =22
Step-by-step explanation:
We know that the diagonals of a parallelogram bisect each other
so 2a = 3b+2
and 2a+3 = 6b-1
We know have a system of equations to solve
2a = 3b+2
2a+3 = 6b-1
Subtract 3 from each side
2a+3-3 = 6b-1-3
2a = 6b -4
Now we can set the 2 equations equal ( 2a = 3b+2 and 2a = 6b -4)
3b+2 = 6b-4
Subtract 3b from each side
3b-3b+2 = 6b-3b-4
2 = 3b-4
Add 4 to each side
2+4 = 3b-4+4
6 = 3b
Divide by 3
6/3 = 3b/3
2 =b
We want to find a
2a = 3b+2
Substitute in b=2
2a = 3(2) + 2
2a = 6+2
2a =8
Divide by 2
2a/2 =8/2
a = 4
Now that we know a and b
EG = 2a + 3b+2
= 2(4) + 3(2)+2
= 8+6+2
= 16
FH = 2a+3 + 6b-1
= 2(4) +3 +6(2)-1
= 8+3+12-1
= 23-1
= 22
Answer:
Her usual driving speed is 38 miles per hour.
Step-by-step explanation:
We know that:
In which s is the speed, in miles per hour, d is the distance, in miles, and t is the time, in hours.
We have that:
At speed s, she takes two hours to drive. So
However, on one particular trip, after 40% of the drive, she had to reduce her speed by 30 miles per hour, driving at this slower speed for the rest of the trip. This particular trip took her 228 minutes.
228 minutes is 3.8 hours. So
So
Her usual driving speed is 38 miles per hour.
