The solutions will try and equilibrate. This means the higher solution will enter the cell via osmosis. The cell will then burst (lysis) or, if it is a plant cell, will become turgid.
The right option is transitive
inference
Transitive inference is a form of
deductive reasoning in which the relationship between items that have not been
clearly assessed is derived. Transitive inference gives the ability to conclude
that if item A is related to Item B and Item B is related to Item D, then Item
A must be related to Item D. From the question given above, the understanding
demonstrates transitive inference.
Answer:
C. releases chemotaxic signals to attract sperm to its location.
Explanation:
An oocyte is female gametocyte which is involved in the reproduction. It is produced in ovary during the female gametogenesis. After ovulation, during luteal phase, egg is available to be fertilized by the sperm.
Sperm are attracted toward the eggs by the process of chemotaxis which is by following the gradient of chemical secreted by egg.
<u>Thus, the oocytes in the female body control not only type of sperm they want ot attract, but also time at which they attract them. </u>
Answer: 1/8 (approximately 12.5%)
Explanation:
The key to figuring out this question is contained in the statement “The alleles at these 2 gene loci assort independently”. This means that the analysis of each locus can be undertaken in isolation first.
1) Let S = straight hair; C = curly hair. Since both alleles are codominant, it can be assumed that the straight-haired man has ‘SS’ genotype and the wavy-haired woman is heterozygous (“SC”). The Punnett chart is as follows:
S C
S SS SC
S SS SC
Thus, there is a 1/2 (50%) chance that any one of their offspring will have wavy hair.
2) We know that the man and the woman have blood types A and B respectively, but we also know that they have already had one child with type 0 blood. Since the only possible genotype for type 0 blood is “00”, and each “0” allele must have been inherited from one of the parents, we can assume that the parents have ”A0” and “B0” genotypes. See chart:
B 0
A AB A0
0 B0 00
There is a 1/4 (25%) chance that any one of their offspring will have type AB blood.
3) Finally: Since the alleles are segregated independently, we may apply the rule of multiplication for probabilities of independent events, as follows:
Probability of wavy hair x probability of type AB blood = 1/2 x 1/4 = 1/8