Answer:
A parabola
Step-by-step explanation:
It's a quadratic equation so the graph will be a parabola.
The solutions are -2 and -7
Hello once again!
When you see a question like this, you need to find the equation of the straight line.
The formular used is y = mx + c
Where
m = slope
c = constant
First find the slope, since it's a straight line, any 2 coordinates can be used.
Now we need to substitude in the slope, and one of the coordinate you used to find the slope, to the formular to find the constant.
In this case i'm using the coordinate
(-2, 16)
y = mx + c
16 = -6(-2) + c
16 = 12 + c
c = 4
∴ The equation of the line is y = -6x + 4
The next step is to simply substitude in the x = 8 to the equation to find y.
y = -6(8) + 4
y = -48 + 4
y = -44
12-pack for 1.69 is a better buy
<em><u>Solution:</u></em>
Given that, Mike bought a 12-pack for 1.69 and Mary bought a 24-pack for 3.18
We have to find which is the better buy
First we have to find the unit rate
Unit rate is cost of 1 pack
<em><u>Mike bought a 12-pack for 1.69</u></em>
Therefore,
Cost of 12 pack = 1.69
Cost of 1 pack is found by dividing 1.69 by 12

Thus unit rate of Mike is 0.14083 dollar per pack
<em><u>Mary bought a 24-pack for 3.18</u></em>
Cost of 24 pack = 3.18
Cost of 1 pack is found by dividing 3.18 by 24

Thus unit rate of Mary is 0.1325 dollars
<em><u>On comparing both the unit rate</u></em>

Thus unit rate of Mike is larger
Thus, 12-pack for 1.69 is a better buy
The capital formation of the investment function over a given period is the
accumulated capital for the period.
- (a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.
- (b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.
Reasons:
(a) The given investment function is presented as follows;

(a) The capital formation is given as follows;

From the end of the second year to the end of the fifth year, we have;
The end of the second year can be taken as the beginning of the third year.
Therefore, for the three years; Year 3, year 4, and year 5, we have;

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87
(b) When the capital stock exceeds $100,000, we have;
![\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%20%5Cmathbf%7B%5Cleft%5B1000%20%5Ccdot%20%20e%5E%7B0.1%20%5Ccdot%20t%7D%7D%20%2B%20C%20%5Cright%5D%5Et_0%7D%20%3D%20100%2C000)
Which gives;




The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.
Learn more investment function here:
brainly.com/question/25300925
Answer and Explanation:
The line seems to pass trough the points (0,6) and (-3,4).
Slope is: 

The slope of the line should be
.