All categories

3 years ago

Find the roots. 2x^2 + 4x - 5 =0

Mathematics

1 answer:

xz_007 [3.2K]3 years ago

8 0

Answer:

$-1\pm\dfrac{\sqrt{14}}{2}$

Step-by-step explanation:

$2x^2+4x-5=0$

Using the quadratic formula:

$x=\dfrac{-4\pm \sqrt{16+40}}{4}=-1\pm\dfrac{\sqrt{14}}{2}$

Hope this helps!

You might be interested in

Javier works each weekend at an animal shelter. He earns $8 an hour. He is saving his earnings to go on a ski trip that costs $1

Harman [31]

Answer:

Step-by-step explanation:

She earns $8/hour

And she works weekend only

He is saving his earning to go for ski and it cost $190

For him to save $190, let know the hours he is going to work

He earns $8/hour and need $190,

Then he is going to work for

190/8=23.75hours

At least, he needs to work for 24hours and since the 24hours is in a day then, Becca his wrong, he doesn't need extra to work extra 6hours.

We are not told if he need to buy something or do something else we are only told he needs $190 for the trip

4 0

3 years ago

Suppose a plane flies 48 miles in 12 minutes. The relationship between miles flown, x, and minutes flown, y, by the plane can re

Molodets [167]

Answer:

112.

Step-by-step explanation:

5 0

2 years ago

Find the circumference of the circle.

Vesna [10]

Assuming 13 is the radius the answer is 81.64cm

5 0

3 years ago

-4x - 10x<br> Combine Like Terms

kondaur [170]

Answer:

-14x

Step-by-step explanation:

-4x+-10x =-14x

5 0

3 years ago

Read 2 more answers

Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)

USPshnik [31]

First, expand the terms inside the bracket you will get

$(( \tan {}^{2} (x) + 2 \tan(x) \sin(x) + \sin {}^{2} (x) - ( \tan {}^{2} (x) - 2 \tan(x) + \sin {}^{2} (x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$( 4 \tan(x) \sin(x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) \sin {}^{2} (x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) (1 - \cos {}^{2} (x) ) = 16 (\tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan {}^{2} (x) - \frac{ \sin {}^{2} (x) \cos {}^{2} ( {x}^{} ) }{ \cos {}^{2} (x) }$

$16( \tan {}^{2} (x) - \sin {}^{2} (x) ) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

5 0

2 years ago