3 years ago

Find the value of a1 for an infinite geometric with series with s=9 and r=1/6

1 answer:

3 0

Heres how to solve it
An infinite geometric series is the sum of an infinite geometric sequence. This series would have no last term. The general form of the infinite geometric series is a1+a1r+a1r2+a1r3+...a1+a1r+a1r2+a1r3+... , where a1a1 is the first term and rr is the common ratio

You might be interested in

I need help please!! Can someone help me please

Talja [164]

Answer:

The pictures is unclear resend again.

5 0

3 years ago

100 points. Which is the graph of f (x) x - 1/ x2 - x 6

Dovator [93]

Answer: the answer is c

Step-by-step explanation:

5 0

1 year ago

Write in factored form:<br><br> 13x - 26

iogann1982 [59]

Factored form is x-2

6 0

3 years ago

Read 2 more answers

Why are 5 and -5 opposites?

Orlov [11]

Answer:

5 is a posotive number and -5 is a negitave number

Step-by-step explanation:

5 0

3 years ago

Solve for x. (e^x-e^-x)/((e^x+e^-x)=t

Sergio [31]

$\dfrac{e^x-e^{-x}}{e^x+e^{-x}}=t\\\\
\dfrac{e^{2x}-1}{e^{2x}+1}=t\\\\
e^{2x}-1=t(e^{2x}+1)\\\\
e^{2x}-1=e^{2x}t+t\\\\
e^{2x}-e^{2x}t=t+1\\\\
e^{2x}(1-t)=t+1\\\\
e^{2x}=\dfrac{t+1}{1-t}\\\\
e^{2x}=-\dfrac{t+1}{t-1}\\\\
2x=\ln\left(-\dfrac{t+1}{t-1}\right)\\\\
x=\dfrac{\ln\left(-\dfrac{t+1}{t-1}\right)}{2}\qquad t\in(-1,1)



$

8 0

4 years ago

Read 2 more answers