Question

1: make x the subject: 4(x+y) = z 2: make b the subject: ab + cd = e

Answer 1

Answer:

1.x=(z/4)-y

2.b=(e-cd)/a

Step-by-step explanation:

1.

z=4(x+y)

Divide both sides by 4

z/4=x+y

Subtract y from both sides

(z/4)-y=x

Answer

x=(z/4)-y

2.

ab+cd=e

subtract cd from both sides

ab=e-cd

divide both sides by a

b=(e-cd)/a

Answer

b=(e-cd)/a

Answer 2

Answer:

$1) x = \frac{z}{4} - y$

$2) b = \frac{e}{a} - \frac{cd}{a}$

Explanation:

(1) Making x the subject: $4(x + y) = z$

To make x the subject of original expression, we send the x to the left side of expression and all of the other components to the right side of expression.

The detail procedure is described as following:

    $4(x + y) = z$

Apply associate property:

<=> $4x + 4y = z$

Send 4y to the right side (the sign of 4y must be changed from positive to negative):

<=> $4x = z - 4y$

Divide both sides by 4:

<=> $x = \frac{z}{4} - y$

(2) Make b the subject: $ab + cd = e$,  applying the similar procedure in part (1):

      $ab + cd = e$

Send $cd$ to the right side (the sign of

<=> $ab = e - cd$

Divide both sides by $a$:

<=> $b = \frac{e}{a} - \frac{cd}{a}$

Hope this helps!

:)