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3 years ago

What is an orbital?

Chemistry

2 answers:

goldfiish [28.3K]3 years ago

7 0

An orbit is the path one object in space takes around another

Vlada [557]3 years ago

4 0

Has to do with an Orbit or Orbits

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it is defined as looking for information by asking various questions about the thing you are curious about?

tino4ka555 [31]

Answer:

Inquiry.

Explanation:

Inquiry can be defined as the process (act) of looking for information by asking various questions about the thing you are curious about.

Simply stated, an inquiry is an act that typically involves seeking information by asking questions with respect to the thing you have curiosity for or the thing you wish to know more about.

This ultimately implies that, an inquiry deals with the urge to find information, seek for the truth or knowledge, examine principles and facts about the thing you are curious about.

3 0

3 years ago

Which one of the following is a vestigial structure? 1. Heart 2. Appendix 3. Right leg 4. liver

marysya [2.9K]

Im going to say that it is 1.) The Heart

4 0

3 years ago

Read 2 more answers

A chemical feature that distinguishes a saturated fatty acid from an unsaturated fatty acid is the:

Sedaia [141]

Presence of single C-C bond
(unsaturated has C=C)

3 0

3 years ago

The pH of a solution prepared by the addition of 100mL 0.002M HCL to 100mL distilled water is closest to:

IRISSAK [1]

Answer:

d.3.0

Explanation:

Step 1: Calculate the final volume of the solution

The final volume is equal to the sum of the volumes of the initial HCl solution and the volume of distilled water.

V₂ = 100 mL + 100 mL = 200 mL

Step 2: Calculate the final concentration of HCl

We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂ = 0.002 M × 100 mL/200 mL = 0.001 M

Step 3: Calculate the pH of the final HCl solution

Since HCl is a strong acid, [H⁺] = HCl. We will use the definition of pH.

pH = -log [H⁺] = -log 0.001 = 3

7 0

3 years ago

A 5.325g sample of methyl benzoate, a compound in perfumes , was found to contain 3.758 g of carbon, 0.316 g of hydrogen, and 1.

Alexxandr [17]

Answer: The empirical and molecular formula of the compound is $C_4H_4O$ and $C_8H_8O_2$ respectively

Explanation:

We are given:

Mass of C = 3.758 g

Mass of H = 0.316 g

Mass of O = 1.251 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{3.758g}{12g/mole}=0.313moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.316g}{1g/mole}=0.316moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.251g}{16g/mole}=0.078moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.078 moles.

For Carbon = $\frac{0.313}{0.078}=4.01\approx 4$

For Hydrogen = $\frac{0.316}{0.078}=4.05\approx 4$

For Oxygen = $\frac{0.078}{0.078}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 4 : 4 : 1

The empirical formula for the given compound is $C_4H_4O$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

$n=\frac{\text{Molecular mass}}{\text{Empirical mass}}$

We are given:

Mass of molecular formula = 130 g/mol

Mass of empirical formula = 68 g/mol

Putting values in above equation, we get:

$n=\frac{130g/mol}{68g/mol}=1.9\approx 2$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(2\times 4)}H_{(2\times 4)}O_{(2\times 2)}=C_8H_8O_2$

Hence, the empirical and molecular formula of the compound is $C_4H_4O$ and $C_8H_8O_2$ respectively

4 0

3 years ago

What is an orbital?​

What is an orbital?