You would equal the equations together then solve for a variable.
-4x - 3 = -2x + 1
-4x + 2x = 1 + 3
-2x = 4
—— —-
-2 -2
x = -2
then take that x value and substitute it into any one of the equations.
Equation #1
y = -4(-2) -3
= 8 - 3
= 5
Equation #2
y = -2(-2) + 1
= 4 + 1
= 5
Rewrite the fractions to have a common denominator to find the difference:
2/3 = 4/6
Difference = 4/6-5/6 = -1/6
Sequence formula = an = a1 + d(n-1)
A1 is the first term 5/6
And d = -1/6
Sequence = 5/6 -1/6(n-1)
Simplify to get an =(-n +6)/6
Answer:
13.4
Step-by-step explanation:
1/3 * 3x + 5.2y
1/3 * 3(3) + 5.2(2)
1/27 + 10.4
Answer:
114
Step-by-step explanation:
15 x 2 + 9 x 2 + 11 x 3 + 11 x 3 = 114
(the bottom portion is equal to 3 x 11)
Answer:
5?
Step-by-step explanation:
2x › 5 (buy at least 4)
so you can just start plugging numbers in.
I used 5, 5 times 2 is 10 which is 5 more that 5, which does met the quota.