All categories

3 years ago

If BC = 15, BE = 6, DC = 12, and AD = 8, then segment DE is parallel to segment AB.

2 answers:

4 0

Solution: if BC = 15 - 6 = 9

Use the converse of triangle proportionality theorem

AD/DC = 8/12 = 2/3
BE/EC = 6/9 = 2/3

Answer: yes, AD/DC =BE/EC = 2/3, so DB||AB

Elis [28]3 years ago

3 0

Do you have a picture? Your question isn’t making sense love

You might be interested in

Practice using the work formula. A bathtub that holds 42 gallons of water is filling at a rate of 4 gallons per minute. How long

trapecia [35]

Answer: The percentage of the tub after 6 minutes is 30 %

Step-by-step explanation: The calculation can be done as follows

1 minutes= 4 gallons

6 minutes= 4×6

= 24 minutes

If the bathtub can hold 80 gallons of water then the percentage of the tub after 6 minutes can be calculated as follows

= 24/80

= 0.3 × 100

= 30 %

Hence the percentage of the tub will be filled after 6 minutes is 30 %

Please see the link below for more information

4 0

2 years ago

Find the quotient of 1 4 ÷ 3 8 in simplest form

Otrada [13]

Is that suppose to be 14/38?

4 0

3 years ago

Read 2 more answers

A machine at a bottling company fills water bottles. the number of bottles filled is proportional to the amount of time the mach

Whitepunk [10]

In the table shown below:

Let N be the number of bottles filled,

Let T be the time in hours.

Given that the number of bottles filled is proportional to the amount of time the machine runs, we have

$\begin{gathered} N\propto T \\ \text{Introducing a proportionality constant, we have } \\ N\text{ = kT} \\ \Rightarrow k\text{ = }\frac{N}{T} \\ \end{gathered}$

Let's evaluate the value of k for each day.

Thus, on monday,

$\begin{gathered} N\text{ = 9900} \\ T\text{ = 5.5} \\ \text{thus,} \\ k\text{ = }\frac{9900}{5.5} \\ \Rightarrow k\text{ = 1800} \end{gathered}$

Tuesday:

$\begin{gathered} N\text{ = }11160 \\ T\text{ = }6.2 \\ \text{thus,} \\ k\text{ = }\frac{11160}{6.2} \\ \Rightarrow k\text{ = 1800} \end{gathered}$

Wednesday:

$\begin{gathered} N\text{ = }12330 \\ T\text{ = }6.25 \\ \text{thus,} \\ k\text{ = }\frac{12330}{6.25} \\ \Rightarrow k\text{ = 1972.8} \end{gathered}$

Thursday:

$\begin{gathered} N\text{ = }10440 \\ T\text{ = }5.80 \\ \text{thus,} \\ k\text{ = }\frac{10440}{5.8} \\ \Rightarrow k=1800 \end{gathered}$

It is observed that all exept wednesday have the same value of k.

Thus, the amount of time required for the number of bottles filled on wednesday is evaluated as

$\begin{gathered} N\text{ = }12330 \\ k\text{ = 1800} \\ T\text{ = ?} \\ \text{but} \\ k\text{ = }\frac{N}{T} \\ 1800\text{ = }\frac{12330}{T} \\ \Rightarrow T\text{ = }\frac{\text{12330}}{1800} \\ T\text{ = 6.85} \end{gathered}$

Hence, the incorrect day is Wednesday. The amount of time for that many bottles should be 6.85 hours.

3 0

1 year ago

A horse ran 800 meters in 40 seconds , 1200 meters in 60 seconds , and 480 meters in 24 seconds . Is this a proportional relatio

frosja888 [35]

Answer:

This is a proportional relationship, the constant of proportionality is 20m/s and it represents that the horse can run 20 meters every second.

Equation: d = 20s, where d=distance and s=number of seconds.

Step-by-step explanation:

In order to find out whether this relationship is proportional, you need to see if the rate at which the horse runs is constant (the same). If you look at the three sets of data (24, 480), (40, 800) and (60, 1200) where the pair is (seconds, meters), you can see that for any two sets of data the change in meters divided by the change in seconds is consistently 20m/s. For example:

$\frac{1200-800}{60-40}=\frac{400}{20}=20$

Since the constant is 20, we know that the horse can run 20 meters every second. To find the horse's total distance, we need to multiply the rate by the number of seconds that it runs:

d = 20s

8 0

4 years ago

Use properties to find the sum or product. 93+(68+7)

erma4kov [3.2K]

$93+(68+7)=93+68+7\\use\ commutative\ property: a+b=b+a\\\\=93+7+68\\use\ associative\ property:a+(b+c)=(a+b)+c\\\\=(93+7)+68=100+68=\huge\boxed{168}$

6 0

3 years ago