What is the value of x?
2 answers:
<em>So</em><em> </em><em>the</em><em> </em><em>va</em><em>lue</em><em> </em><em>of</em><em> </em><em>X</em><em> </em><em>is</em><em> </em><em>5</em><em>0</em>
<em>look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em>
<em>G</em><em>ood</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
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Answer:
B' (16, 14)
Step-by-step explanation:
<em>Whenever we have a dilation with a scale factor b, we get the new point as:</em>
<em>Let original point be (x,y), then the dilation would make it (bx, by).</em>
<em />
There is a diagonal that goes through AC and another through BD. The midpoint of both the diagonal is same. Midpoint formula is:
<u>Midpoint of AC:</u>
Now let vertex B have coordinates (x,y). <u>Midpoint of BD:</u>
<em>Equate this to the midpoint of AC:</em>
<em>(x+2)/2=5</em>
<em>x+2 = 10</em>
<em>x = 8</em>
<em />
<em>and</em>
(y+1)/2=4
y+1=8
y = 7
Thus, B(8,7)
<em>recalling dilation of scale factor 2 rule we said at the beginning, B' would be twice of each coordinate. Hence B' = (16,14)</em>