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Alexandra [31]
4 years ago
7

Correct answers only please!

Mathematics
1 answer:
lutik1710 [3]4 years ago
4 0

Answer:

$1512

Step-by-step explanation:

Using the given formula :

I = P × R × T

I = 75600 × 1/100 × 2

I = $1512

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1. The sides of a triangle are in the ratio 3:4:5 What is the length of each side if the perimeter
Nataly_w [17]

Answer:

22.5 cm, 30 cm, 37.5 cm

Step-by-step explanation:

Sum the parts of the ratio, 3 + 4 + 5 = 12 parts

Divide the perimeter by 12 to find the value of one part of the ratio.

90 cm ÷ 12 = 7.5 cm ← value of 1 part of the ratio, thus

3 parts = 3 × 7.5 cm = 22.5 cm

4 parts = 4 × 7.5 cm = 30 cm

5 parts = 5 × 7.5 cm = 37.5 cm

The 3 sides are 22.5 cm, 30 cm and 37.5 cm

7 0
4 years ago
a survey asked 50 students if they play an instrument and if they are in band. 25 students play an instrument 20 are in a band a
frutty [35]
I would go with d .... If not it would be c...


Really hope I help but I would choose d
5 0
4 years ago
Read 2 more answers
Find an equation of the line having the given slope and containing the given point.
saul85 [17]

Answer:

y = 4x - 12

Step-by-step explanation:

The equation of a line has the following format:

y = mx + b

In which m is the slope and b is the y-intercept(value of x when y = 0).

In this question:

Slope 4, which means that m = 4.

So

y = 4x + b

Contains point (1,-8).

This means that when x = 1, y = -8. We replace this into the equation to find b. So

y = 4x + b

-8 = 4(1) + b

b = -12

So

y = 4x - 12

4 0
3 years ago
Answer for a lot of points!
earnstyle [38]

Given :

  • ZC = 90°

  • CD is the altitude to AB.

  • \angleA = 65°.

To find :

  • the angles in △CBD and △CAD if m∠A = 65°

Solution :

In Right angle △ABC,

we have,

=> ACB = 90°

=> \angleCAB = 65°.

So,

=> \angleACB + \angleCAB+\angleZCBA = 180° (By angle sum Property.)

=> 90° + 65° + \angleCBA = 180°

=> 155° +\angleCBA = 180°

=> \angleCBA = 180° - 155°

=> \angleCBA = 25°.

In △CDB,

=> CD is the altitude to AB.

So,

=> \angle CDB = 90°

=> \angleCBD = \angleCBA = 25°.

So,

=> \angleCBD + \angleDCB = 180° (Angle sum Property.)

=> 90° +25° + \angleDCB = 180°

=> 115° + \angleDCB = 180°

=> \angleDCB = 180° - 115°

=> \angleDCB = 65°.

Now, in △ADC,

=> CD is the altitude to AB.

So,

=> \angleADC = 90°

=>\angle CAD =\angle CAB = 65°.

So,

=> \angleADC + \angleCAD +\angleDCA = 180° (Angle sum Property.)

=> 90° + 65° + \angleDCA = 180°

=> 155° +\angleDCA = 180°

=> \angleDCA = 180° - 155°

=> \angleDCA = 25°

Hence, we get,

  • \angleDCA = 25°
  • \angleDCB = 65°
  • \angleCDB = 90°
  • \angleACD = 25°
  • \angleADC = 90°.
7 0
3 years ago
What is the perimeter of the parrelogram<br> Pls
olga55 [171]

Answer:32

Step-by-step explanation:

perimeter is the sum of the length of its four sides

2l plus 2w

  • 8 multiply 2=6
  • 12 multiply 2=24
  • 24plus 8 =32
  • l =8
  • w=12
6 0
3 years ago
Read 2 more answers
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