Answer:
B) 2 1/4
Step-by-step explanation:
Answer:
2(n+1)+2
You start with two greens and two columns of two orange squares while adding two orange squares each time. So, the bolded part is the green squares that stay the same. The 2(n+1) represents the two orange columns that increase by one block on each side per image.
Go 0.35•22 and you get 7.7
Answer:
71.123 mph ≤ μ ≤ 77.277 mph
Step-by-step explanation:
Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:
≤ μ ≤ 
Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and 
is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.
the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.
So, if we replace m by 74.2, s by 5.3083, n by 10 and 
by 1.8331, we get that the 90% confidence interval for the mean speed is:
≤ μ ≤ 
74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077
71.123 ≤ μ ≤ 77.277
The correct answer is C. The form for shifts is (x-h)^2 +k where h=the x variable ( horizontal shift left or right) and k = the y variable (vertical shift up or down) The confusing part for many students is remember that if you are moving left it's subtraction So in the form x-h it is actually x - (-h) so it gets turned into a positive/ addition sign.
