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Oliga [24]
3 years ago
10

Question mark 1: Match the triangle to correct function and answer

Mathematics
1 answer:
postnew [5]3 years ago
8 0

Answer:

Triangle 1 - m\angle A = 58^{\circ}, hypotenuse = 16

x \approx 8.479

Triangle 2 - m \angle A = 44^{\circ}, adjacent leg = 18

x \approx 17.382

Triangle 3 - m\angle A = 49^{\circ}, opposite leg = 12

x \approx 15.900

Step-by-step explanation:

Each triangle is solved by means of trigonometric relations:

Triangle 1 - m\angle A = 58^{\circ}, hypotenuse = 16

\cos 58^{\circ} = \frac{x}{16}

x = 16\cdot \cos 58^{\circ}

x \approx 8.479

Triangle 2 - m \angle A = 44^{\circ}, adjacent leg = 18

\tan 44^{\circ} = \frac{x}{18}

x = 18\cdot \tan 44^{\circ}

x \approx 17.382

Triangle 3 - m\angle A = 49^{\circ}, opposite leg = 12

\sin 49^{\circ} = \frac{12}{x}

x = \frac{12}{\sin 49^{\circ}}

x \approx 15.900

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Answer: 9 (with a margin of: 0)

Step-by-step explanation:

Times everything by 5

That gives you 15 + 10w = 105.

Subtract 15 from both sides

Divide by 10 to get w by itself

Then you solve

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3 years ago
Find the areas of the shapes​
likoan [24]

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Step-by-step explanation:

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3 years ago
Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos
Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$ P_{1} = (- 1, 4) $

$ P_{2} = (6, 2) $    and

$ P_{3} = (4, - 5) $

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $ (x_1, y_1) $ and $ (x_2, y_2) $ is:

                                 $ \sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+}   \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}} $

Length between $ P_1 $ and $ P_{2} $ , (Side 1) :

$ (x_1, y_1) = (- 1, 4) $     and

$ (x_2, y_2) = (6, 2) $

Distance = $ \sqrt{\bigg(6 - (-1) \bigg)^{2} \hspace{1mm} + \hspace{1mm} \bigg( 2 - 4 \bigg )^2 $

$ = \sqrt{7^2 + 2^2} $

$ = \sqrt{49 + 4} $

$ = \sqrt{\textbf{53}} $

Length of Side 1 = $  \sqrt{\textbf{53}} $ units.

Distance between $ P_1 $ and P_2 , (Side 2):

$ (x_1, y_1) = (-1, 4) $

$ (x_2, y_2) = (4, - 5) $

Distance = $ \sqrt{ \bigg( 4 + 1 \bigg)^2 \hspace{1mm} + \bigg( - 5 - 4 \bigg ) ^2 $

$ = \sqrt{ 25 + 81 } $

$ = \sqrt{\textbf{106}} $

Length of Side 2 = $ \sqrt{\textbf{106}} $ units.

Distance between $ P_2 $ and $ P_3 $ , Side 3 :

$ (x_1, y_1) = (4, 5) $

$ (x_2, y_2) = (6, 2) $

Distance = $ \sqrt{ 2^2 \hspace{1mm} + \hspace{1mm} 7^2} $

$ = \sqrt{49 + 4} $

$ = \sqrt{\textbf{53} $

Length of Side 3  = $ \sqrt{\textbf{53}} $ units.

Note that the length of Side 1 = Length of Side 3.

That means the triangle is Isosceles.

Also, For a triangle to be right angle triangle, using Pythagoras theorem we have:

(Side 1)² + (Side 3)² = (Side 2)²

$ \bigg( \sqrt{53} \bigg )^2 \hspace{1mm} + \hspace{1mm} \bigg( \sqrt{53} \bigg)^2 \hspace{1mm} = \hspace{1mm} \bigg ( \sqrt{106} \bigg ) ^2 $

i.e, 53 + 53  = 106

Hence, the triangle is a right - angled triangle as well.

7 0
3 years ago
How do u work this out and what's the answer
I am Lyosha [343]
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3) 1 5/4 - 3/4 = 1 2/4, which simplified version is 1 1/2
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3 years ago
A merchant has coffee worth $20.00 per pound that she wishes to mix with 70 pounds of coffee with​ $90.00 per pound to get a mix
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75 The mix will be 75 lbs

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