Answer:
Step-by-step explanation:
Given that a basketball coach will select the members of a five-player team from among 9 players, including John and Peter.
Out of nine players five are chosen at random.
The team consists of John and Peter.
Hence we can sort 9 players as I group, John and Peter and II group 7 players.
Now the selection is 2 from I group and remaining 3 from II group.
Hence no of ways of selecting a team that includes both John and Peter==35
Total no of ways = =126
= =
The answer is 566m because 147 plus 147 and 136 plus 136 equals 566
Would it be 9 because 8 times 3 equals 24 and 3 times 3 equals 9
Answer:
Try this
Step-by-step explanation:
So what you have to do is turn 65% into a decimal. 65% as a decimal is 0.65.
Then what you want to do is divide 5.00 and 0.65 and see what you get.