An African elephant weighed 209 lbs when it was born. Baby elephants gain an average of 38 lbs per week.
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Answer:
Probability of at least 50 obese individuals in our sample is 0.92364 .
Step-by-step explanation:
We are given that a random sample of 300 adults is taken from the state of Colorado, where the rate of obesity is 19.8% .
Let X = Number of obese individuals
Firstly, X ~
For approximating binomial distribution into normal distribution, firstly we have to calculate and
.
Mean of Normal distribution, = n * p = 300 * 0.198 = 59.4
Variance of Normal distribution, = n * p * (1-p) = 300 *0.198 *0.802 = 47.64
So, now X ~ N()
The standard normal z score distribution is given by;
Z = ~ N(0,1)
So, probability of at least 50 obese individuals in our sample = P(X >= 50)
P(X >= 50) = P(X > 49.5) {using continuity correction}
P(X > 49.5) = P( >
) = P(Z > -1.43) = P(Z < 1.43) = 0.92364
Therefore, required probability is 0.92364 .
The expanded form for the number 165.038 is 100+60+5+0.03+0.008.
<h3>What is the expended form of decimal numbers?</h3>Writing decimals in expanded form simply means writing each number according to its place value. This is done by multiplying each digit by its place value and adding them together. Let's look at an example: 2.435. In words, we would say this as two and four hundred thirty-five thousandths.
In the given question expended form 100+60+5+30+8 is wrong.
After decimal point the first digit is at the tenth place and second digit at the hundredth place and third is at the thousandth place and so on....
165.038 = 100+60+5++
+
= 100+60+5+0.03+0.008
Hence, The correct expended form of the given number is 100+60+5+0.03+0.008.
To learn more about expended form from the given link:
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