In a single throw of 2 dice find the probability of a sum greater than 9
1 answer:
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Answer:
Step-by-step explanation:
I take it that this is some sort of ratio. Start by solving the brackets on the left.
Brackets: 1/3 - 1/10
Brackets: 10/30 - 3/30
Brackets: 7/30
Brackets^2: 49/900
Brackets^2 - 1/5: 49/900 - 180/900
Brackets^2 - 1/5: -131/900
(2/5)^2 = 4/25
The way this read, it should be
Which when you invert and multiply becomes
which finally becomes