250 divided by 10 squared is 2.5
Cross multiplying we get
x^2 = 2*7x
x^2 = 14x
x^2 - 14x = 0 is the answer
Answer:
b₁ = (2a – b₂h)/h; b₁ = (2a)/h – b₂; h = (2a)/(b₁ + b₂)
Step-by-step explanation:
A. <em>Solve for b₁
</em>
a = ½(b₁ + b₂)h Multiply each side by 2
2a = (b₁ + b₂)h Remove parentheses
2a = b₁h + b₂h Subtract b₂h from each side
2a - b₂h = b₁h Divide each side by h
b₁ = (2a – b₂h)/h Remove parentheses
b₁ = (2a)/h – b₂
B. <em>Solve for h
</em>
2a = (b₁ + b₂)h Divide each side by (b₁ + b₂)
h = (2a)/(b₁ + b₂)
Answer:
Yes
Step-by-step explanation:
- the probability that a person has the virus given that they have tested positive is 0.0151.
- the probability that a person does not have the virus given that they have tested negative is 0.9999
P(A) = 1/600 = 0.0017
P(B) = 0.9 * 0.0017 + 0.1 * (1 - 0.0017) = 0.1014
A) P (has the virus | tested positive) = P (tested positive | has the virus) ×
P (has the virus)/ P (tested positive)
= 0.9 × 0.0017/0.1014
= 0.0151
B) P (does not have the virus | tested negative) = P (tested negative | does not have the virus) × P (does not have the virus)/ P (tested negative)
= (1 - 0.1) *× (1 - 0.0017)/ (1 - 0.1014)
= 0.9999
Probability is the department of mathematics regarding numerical descriptions of ways likely an occasion is to occur, or how possibly it's far that a proposition is genuine. The possibility of an occasion varies between zero and 1, wherein, roughly speaking, 0 suggests the impossibility of the occasion and 1 shows certainty. The better the possibility of an event, the more likely it is that the event will arise.
A simple instance is the tossing of an honest (unbiased) coin. since the coin is truthful, the 2 results ("heads" and "tails") are both equally likely; the possibility of "heads" equals the chance of "tails"; and considering the fact that no different results are feasible, the possibility of both "heads" or "tails" is 1/2 (that could additionally be written as 0.5 or 50%).
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