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EleoNora [17]
3 years ago
14

Suppose two fair six-sided dice are rolled. what is the probability that they will both come up with the same number?

Mathematics
1 answer:
marta [7]3 years ago
8 0
You have a 16.7% chance of rolling doubles
You might be interested in
1 /x^−1 in simplest rational form
Allushta [10]
Here is a link to help you find the answer:
https://www.khanacademy.org/math/algebra2/rational-expressions-equations-and-functions/simplify-rati...

Hope this helps!
3 0
3 years ago
8 is 2% of what number
bixtya [17]
The answer would be 16. 
8+8=16 
5 0
2 years ago
Read 2 more answers
Use Stokes' Theorem to evaluate C F · dr where C is oriented counterclockwise as viewed from above. F(x, y, z) = yzi + 4xzj + ex
natima [27]

Answer:

The result of the integral is 81π

Step-by-step explanation:

We can use Stoke's Theorem to evaluate the given integral, thus we can write first the theorem:

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot d\vec S

Finding the curl of F.

Given F(x,y,z) = < yz, 4xz, e^{xy} > we have:

curl \vec F =\left|\begin{array}{ccc} \hat i &\hat j&\hat k\\ \cfrac{\partial}{\partial x}& \cfrac{\partial}{\partial y}&\cfrac{\partial}{\partial z}\\yz&4xz&e^{xy}\end{array}\right|

Working with the determinant we get

curl \vec F = \left( \cfrac{\partial}{\partial y}e^{xy}-\cfrac{\partial}{\partial z}4xz\right) \hat i -\left(\cfrac{\partial}{\partial x}e^{xy}-\cfrac{\partial}{\partial z}yz \right) \hat j + \left(\cfrac{\partial}{\partial x} 4xz-\cfrac{\partial}{\partial y}yz \right) \hat k

Working with the partial derivatives

curl \vec F = \left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(4z-z\right) \hat k\\curl \vec F = \left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(3z\right) \hat k

Integrating using Stokes' Theorem

Now that we have the curl we can proceed integrating

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot d\vec S

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S curl \vec F \cdot \hat n dS

where the normal to the circle is just \hat n= \hat k since the normal is perpendicular to it, so we get

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S \left(\left(xe^{xy}-4x\right) \hat i -\left(ye^{xy}-y\right) \hat j + \left(3z\right) \hat k\right) \cdot \hat k dS

Only the z-component will not be 0 after that dot product we get

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S 3z dS

Since the circle is at z = 3 we can just write

\displaystyle \int\limits_C \vec F \cdot d\vec r = \int \int_S 3(3) dS\\\displaystyle \int\limits_C \vec F \cdot d\vec r = 9\int \int_S dS

Thus the integral represents the area of a circle, the given circle x^2+y^2 = 9 has a radius r = 3, so its area is A = \pi r^2 = 9\pi, so we get

\displaystyle \int\limits_C \vec F \cdot d\vec r = 9(9\pi)\\\displaystyle \int\limits_C \vec F \cdot d\vec r = 81 \pi

Thus the result of the integral is 81π

5 0
3 years ago
Aliya is making patches out of a 3 3/4 foot strip of fabric. Her patches will be 1/8 of a foot. How many patches will she be abl
vagabundo [1.1K]

Answer:

tendrá la capacidad de hacer 6 parches

Step-by-step explanation

6 0
2 years ago
identify the image of triangle XYZ for a composition of 50 degrees rotation and a 40 degrees rotation, both about point y
Rudik [331]

Answer:

a

Step-by-step explanation:

Given:

triangle XYZ  is rotated by a composition of 50°+40°=90° both about point y

Now when a geometrical figure is rotated by any degree then its shape or size does not change and remain same.

As the triangle is rotated clockwise by 90  degrees about point y then diagram attached is formed .

option a is correct.

3 0
3 years ago
Read 2 more answers
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