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EleoNora [17]
3 years ago
14

Suppose two fair six-sided dice are rolled. what is the probability that they will both come up with the same number?

Mathematics
1 answer:
marta [7]3 years ago
8 0
You have a 16.7% chance of rolling doubles
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A triangular pyramid has these dimensions.
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Answer: 42 cm3

Step-by-step explanation:

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An architect made a scale drawing of a building. The scale of the drawing is 3 inches equals 50 feet. The actual building has a
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The height in the scale drawing was 250 inches.
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A circle has its center at (-1, 2) and a radius of 3 units. What is the equation of the circle? (1 point) (x - 1)2 + (y + 2)2 =
Nina [5.8K]

Answer:

(x + 1)^2 + (y - 2)^2 = 3^2 = 9

Step-by-step explanation:

The standard equation of a circle with center at (h, k) and radius r is

(x - h)^2 + (y - k)^2 = r^2.

Here, h = -1, k = 2 and r = 3, so the equation of this particular circle is

(x + 1)^2 + (y - 2)^2 = 3^2 = 9.

8 0
3 years ago
SOMEONE PLEASE I NEED HELL AND I WANT TO GO TO SLEEP, but there’s more than one answer btw
ira [324]

Answer:

The second one, third one and the fifth one should be correct. (7 to the 18th power divided 7 to the 9th power, 7 to the 3rd power to the 3rd power, and 7 to the 4th power times 7 to the 5th power)

Step-by-step explanation:

7 to the 8th power times 7 equal 40353607 so if you do all the equations shown you can rule out which ones equal 40353607 and which ones don't. Have a nice sleep!

3 0
2 years ago
Read 2 more answers
ПОЖАЛУЙСТА ПОМОГИТЕ РЕШИТЬ ДАЮ 23 ОЧКА!!!
posledela

(Простите, пожалуйста, мой английский. Русский не мой родной язык. Надеюсь, у вас есть способ перевести это решение. Если нет, возможно, прилагаемое изображение объяснит достаточно.)

Use the shell method. Each shell has a height of 3 - 3/4 <em>y</em> ², radius <em>y</em>, and thickness ∆<em>y</em>, thus contributing an area of 2<em>π</em> <em>y</em> (3 - 3/4 <em>y</em> ²). The total volume of the solid is going to be the sum of infinitely many such shells with 0 ≤ <em>y</em> ≤ 2, thus given by the integral

\displaystyle 2\pi \int_0^2 y \left(3-\frac34 y^2\right) \,\mathrm dy = 2\pi \left(\frac32 y^2 - \frac3{16} y^4\right)\bigg|_0^2 = 6\pi

Or use the disk method. (In the attachment, assume the height is very small.) Each disk has a radius of √(4/3 <em>x</em>), thus contributing an area of <em>π</em> (√(4/3 <em>x</em>))² = 4<em>π</em>/3 <em>x</em>. The total volume of the solid is the sum of infinitely many such disks with 0 ≤ <em>x</em> ≤ 3, or by the integral

\displaystyle \pi \int_0^3 \left(\sqrt{\frac43x}\right)^2 \,\mathrm dx = \frac{2\pi}3 x^2\bigg|_0^3 = 6\pi

Using either method, the volume is 6<em>π</em> ≈ 18,85. I do not know why your textbook gives a solution of 90,43. Perhaps I've misunderstood what it is you're supposed to calculate? On the other hand, textbooks are known to have typographical errors from time to time...

8 0
3 years ago
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