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yuradex [85]
3 years ago
11

Anna cuts four identical circles from a square piece of black poster board as shown. What is the area of the left over poster bo

ard? Use 3.14 for pi.

Mathematics
2 answers:
nydimaria [60]3 years ago
6 0
Formula for a circle: A=Pi*r^2
Diameter:2ft
Radius:1ft
A=3.14*1^2
A=3.14
Multiply by 4
4 squares=12.56ft squared
Formula for a square: A=s^2
A=4^2
A= 16ft squared
To find leftover you need to subtract 12.56 ft from 16 ft to get 3.44 ft squared(A).
andrey2020 [161]3 years ago
3 0

Answer:

A) 3.44 square feet

Step-by-step explanation:

The area of the black poster board would be

A = 4(4) = 16 square feet.

There are 4 identical circles in the poster board.  The formula for the area of a circle is

A = πr²

Since there are 2 circles across the width of the poster board, this means two diameters are 4 feet.  This makes each diameter 2 feet.  The radius of a circle is half of the diameter; this makes the radius 1 feet.  This gives us

A = π(1²) = 3.14(1²) = 3.14

This is the area of each circle.  There are 4 circles in the poster board; this makes

4(3.14) = 12.56

This makes the left over area

16-12.56 = 3.44 square feet

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Answer:

a

  P( \^ p  >  0.775 ) =  0.12798

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Step-by-step explanation:

From the question we are told that

    The population proportion is  p =  0.75

Considering question a  

     The sample size is  n  =  387

Generally the standard deviation of this sampling distribution is  

         \sigma  = \sqrt{ \frac{p(1 - p)}{ n } }    

=>      \sigma  = \sqrt{ \frac{0.75(1 - 0.75)}{ 387 } }    

=>      \sigma  = 0.022    

The sample proportion of cans that are recycled is

                 \^ p =  \frac{ 300}{387 }

=>              \^ p =  0.775

Generally the probability that 300 or more will be recycled is mathematically represented as

         P( \^ p  >  0.775 ) =  P( \frac{\^ p  -  p }{ \sigma }  >  \frac{0.775 - 0.75 }{ 0.022} )

\frac{\^ p  - p }{\sigma }  =  Z (The  \ standardized \  value\  of  \ \^ p  )

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From the z table  the area under the normal curve to the left corresponding to  1.591   is

      P( Z >  1.136)  = 0.12798

=>    P( \^ p  >  0.775 ) =  0.12798

Considering question b

Generally the lower limit of  sample proportion of cans that are recycled is

                 \^ p_1 =  \frac{ 260 }{387 }

=>              \^ p_1  =  0.6718

Generally the upper limit of  sample proportion of cans that are recycled is

                 \^ p_2 =  \frac{ 300}{387 }

=>              \^ p_2  =  0.775

Generally probability that between 260 and 300 will be recycled is mathematically represented as

           P( 0.6718 < p  <  0.775 ) =  P( \frac{0.6718 - 0.75 }{ 0.022}<  \frac{\^ p  -  p }{ \sigma }

=>      P( 0.6718 < p  <  0.775 ) =  P( -3.55 <  Z < 1.136 )

=>        P( 0.6718 < p  <  0.775 ) = P(Z <  1.136 ) -  P( Z <  -3.55 )

From the z table  the area under the normal curve to the left corresponding to  1.136 and  -3.55  is

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and

       P(Z <  1.136 )  = 0.87202

So

       P( 0.6718 < p  <  0.775 ) =  0.87202-  0.00019262

=>   P( 0.6718 < p  <  0.775 ) =0.87183

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