Write an equation in standard form for the line that passes through (3,-1) and (-5,-3)
2 answers:
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Split the surface area into geometric shapes as shown in the figure below.
Top part
The area of one triangle is
A₁ = (1/2)*(10 cm)*(4 cm) = 20 cm²
There are 3 of these triangles.
Vertical sides..
The area of one vertical side is
A₂ = (10 cm)*(6 cm) = 60 cm²
There 3 of them.
Bottom part
The triangle is equilateral with each side = 10 cm, and each angle = 60 deg.
The area is (from the Law of Sines) equal to
A₃ = (1/2)(10 cm)*(10 cm)*sin(60) = 43.3 cm²
The total surface area is
3A₁ + 3A₂ + A₃
= 3*20 + 3*60 + 4.3
= 283.3 cm²
Answer: The surface area is 283.3 cm²
Top part
The area of one triangle is
A₁ = (1/2)*(10 cm)*(4 cm) = 20 cm²
There are 3 of these triangles.
Vertical sides..
The area of one vertical side is
A₂ = (10 cm)*(6 cm) = 60 cm²
There 3 of them.
Bottom part
The triangle is equilateral with each side = 10 cm, and each angle = 60 deg.
The area is (from the Law of Sines) equal to
A₃ = (1/2)(10 cm)*(10 cm)*sin(60) = 43.3 cm²
The total surface area is
3A₁ + 3A₂ + A₃
= 3*20 + 3*60 + 4.3
= 283.3 cm²
Answer: The surface area is 283.3 cm²
The rest of the question is the attached figure
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solution:
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As show in the attached figure
∠M = ∠R = 54.4°
∠N = ∠T = 71.2°
∠O = 180° - (∠M + ∠N) = 180° - (54.4°+71.2°) = 54.4°
∠S = 180° - (∠R + ∠T) = 180° - (54.4°+71.2°) = 54.4°
∠O = ∠S = 36°
∴ Δ MNO is similar to Δ RTS
So, the correct statement:
The triangles each have two given angle measures and one unknown angle measure.
