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algol [13]
3 years ago
9

Simplify 3a^2+15a / a^3 - 25a please help! rational expressions

Mathematics
2 answers:
goblinko [34]3 years ago
8 0
Factor each expression:

\frac{3a(a+5)}{a(a-5)(a+5)}

Eliminate:

\frac{3}{a-5}
Novay_Z [31]3 years ago
5 0
I got 3a^2+40a/a^3

is that right
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Write a verbal phrase for each of the following algebraic expressions.
Scrat [10]

Answer:

a. the product of 11 and x

b. 9 greater than x

c. x less than 18

d. the product of 4 and the difference of x and 3

Step-by-step explanation:

3 0
2 years ago
John is creating a Thanksgiving display at the store where he works, using only canned pumpkin and canned green beans. He needs
mezya [45]

Answer:

The number of Pumpkin can used   = 48 cans

The number of Green Beans can used =   16 cans

Step-by-step explanation:

The ratio of Pumpkin to Green Beans =  3 :  1

So, for every 3 can of Pumpkin, 1 can of green beans is used.

Now, the total number of  John  wants to use = 64

Let us assume the common factor in the ratio is m.

⇒ The number of Pumpkin can used  = 3 m

The number of Green Beans can used = 1 m = m

So, the Total cans used = Number of (Pumpkin + Green Beans) can

⇒ 3 m + m = 64

or, 4 m =  64

⇒ m = 64/ 4 = 16

Hence, The number of Pumpkin can used  = 3 m = 3 x 16 = 48 cans

The number of Green Beans can used = m =  16 cans

3 0
3 years ago
50 POINTS
Tcecarenko [31]

Answer:

<u>Part 1: C. $3,159.30</u>

<u>Part 2. C. –5; –135; –10,935</u>

Step-by-step explanation:

Part 1:

Price of the boat = $ 16,600

Depreciation rate = 14% = 0.14

Time of utilization of the boat = 11 years

Price of the boat after 11 years = Original price * (1 - Depreciation rate)^Time of utilization of the boat

Price of the boat after 11 years = 16,600 * (1 - 0.14)¹¹

Price of the boat after 11 years = 16,600 * 0.1903

<u>Price of the boat after 11 years = $ 3,159.30</u>

Part 2:

Let's find out the first term of the sequence given:

A(1) = -5 * 3¹⁻¹

A(1) = -5 * 1

A(1) = -5

Let's find out the fourth term of the sequence given:

A(4) = -5 * 3⁴⁻¹

A(4) = -5 * 3³

A(4) = -5 * 27

A(4) = -135

Let's find out the eighth term of the sequence given:

A(8) = -5 * 3⁸⁻¹

A(8) = -5 * 3⁷

A(8) = -5 * 2,187

A(8) = -10,935

4 0
2 years ago
There are only green pens and red pens in a box. there are 3 more red pens than green pens in the box. sheila is going to take a
e-lub [12.9K]

Answer: 6 or 9

Step-by-step explanation:

Given the following :

Let the number of green pens = x

Number of red pens = x + 3

Probability of picking same color = 17/35

Taking two pens at random; probability of picking two pens of same color.

Probability of picking red on first pick then red on second pick ; or picking blue on first pick then blue on second pick

Probability = (Required outcome / Total possible outcomes)

Total number of pens = x + x + 3 = 2x + 3

Probability of picking red then red:

P(red first) = (x+3)/2x+3

P(red second) = x+3-1 / 2x+3-1 = (x+2)/2x+2)

Therefore, probability of red then red =

(x+3)/(2x+3) × (x+2)/2x+2)

= (x+3)(x+2) / (2x+3)(2x+2)

Probability of green then green:

P(first green) = x/(2x+3)

P(second green) = (x-1) / (2x+3-1) = (x-1) / (2x+2)

P(green then green) = x(x-1)/(2x+3)(2x+2)

Therefore,

[(x+3)(x+2) / (2x+3)(2x+2)] + [x(x-1)/(2x+3)(2x+2)] = 17/35

(x+3)(x+2)+x(x-1) / (2x+3)(2x+2) = 17/35

Cross multiply :

35(x+3)(x+2)+x(x-1) = 17(2x+3)(2x+2)

35(2x^2 + 4x + 6) = 17(4x^2 + 10x + 6)

70x^2 + 140x + 210 = 68x^2 + 170x + 102

70x^2 - 68x^2 + 140x - 170x + 210 - 102 = 0

2x^2 - 30x + 108 = 0

Now we have a quadratic equation which can be factoeized used using any known factorization method.

Factorizing this, we get

(x-6) = 0 or (x-9) = 0

x = 6 or x = 9

6 0
3 years ago
A class is selling magazines as a fundraiser. Of the 200 magazines sold, Ananda sold 1/8 of them. Gina sold 0.065 of the magazin
Zina [86]
To figure out which sold the most magazines, multiply each number by 200 to find the answer. Let's start with 1/8. 200 * 1/8 = 25. Then 0.065 * 200 = 13.

3/100 * 200 = 6

200 * 0.105 = 21.

Fatima sold the most magazines.
5 0
3 years ago
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