Answer:
Given : EFGH is a parallelogram.
Prove: EG bisects HF and HF bisects EG.
Since, a parallelogram has two pairs of congruent and parallel sides.
Therefore, In parallelogram EFGH,
EF≅GH and EH≅FG
Also, EF║GH and EH║FG
Since,In triangles EKF and GKH,
EF≅HG
Since, EF║HG
⇒∠FEK ≅ ∠HGK and ∠EFK ≅ ∠ GHK ( When two parallel lines are cut by a transversal alternative interior angles are congruent )
⇒ Δ EKF ≅ Δ GKH ( ASA congruence postulate )
⇒ EK ≅ GK and FK ≅ HK ( CPCTC)
⇒ EG bisects HF and HF bisects EG ( Definition of bisector)
Hence proved.
Answer:
Out of 8 slices two are a
Could be expressed as 2/8 or 1/4 or 25%
25% is your answer
Step-by-step explanation:
Answer:
x-2i
Step-by-step explanation:
Complex roots come in pairs, called complex conjugates
If you have a root a+bi, the other root is a-bi
Since you have one root x+2i, the other root is x-2i
Answer:
7.28
Step-by-step explanation.
4 is rounded down to 80 and if you just take away the 0 in 80 its 8.