In a quadrilateral ABCD where AB║DC point O is the intersection of its diagonals, ∠A and ∠B are supplementary. Point M∈BC and po
int K∈AD , so that O∈MK. Prove that
MO≅KO.
1 answer:
Answer:
The answer to this question can be described as follows:
Step-by-step explanation:
- In Additional A and B implies, that ABCD is a parallelogram. So, there diagonals AC and BD were intersecting.
- AKO and CMO are similar to BC, for they are congruent. There are, therefore, congruent of MCO and KAO.
- The AOK and COM triangles are at least identical, so these triangles are congruent because the bisects AC are of BD .
- Then KO and MO are congruent since they are matching congrue sides, that's why MO≅KO is its points.
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