Find the equation of the straight line passing through the point (3,5) which is perpendicular to the line y=3x+2
2 answers:
Answer:
y=-1/3x+6 .Hope this helps
Answer:
3y = -x + 18
Step-by-step explanation:
Given the equation y = 3x + 2;
By comparison with the general equation
y = mx + C ; where m is the slope
We see that m = 3
Now for a perpendicular line and it's slope is -1/m = -1/3 and let it be M2
But the new slope cuts across points (3,5) .
It means M2 = y - 5/ x-3
-1/3 = y-5/ x-3
-1(x-3) = 3(y-5)
-x +3 = 3y -15
3y = -x + 18
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