Find the equation of the straight line passing through the point (3,5) which is perpendicular to the line y=3x+2

Mathematics

2 answers:

ohaa [14]3 years ago

5 0

Answer:

y=-1/3x+6 .Hope this helps

dedylja [7]3 years ago

3 0

Answer:

3y = -x + 18

Step-by-step explanation:

Given the equation y = 3x + 2;

By comparison with the general equation

y = mx + C ; where m is the slope

We see that m = 3

Now for a perpendicular line and it's slope is -1/m = -1/3 and let it be M2

But the new slope cuts across points (3,5) .

It means M2 = y - 5/ x-3

-1/3 = y-5/ x-3

-1(x-3) = 3(y-5)

-x +3 = 3y -15

3y = -x + 18

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ozzi

Answer:

the answer is C

Step-by-step explanation:

6 0

3 years ago

Find the equation of a line that passes through the point (3,1) and has a gradient of -3. Leave your answer in the form y = m x

Bingel [31]

Answer:

$y = (-3)\, x + 10$ .

Step-by-step explanation:

The question requires that the equation should be in the slope-intercept form $y = m \, x + c$ . The $m$ and $c$ in this equation are constants. In particular:

$m\!$ would represent the slope of this line (also known as the gradient of this line,) whereas
$c$ would be the $y$ -intercept of this line.

The question states that the slope of this line is $(-3)$ . Therefore, $m = -3$ . Thus, the equation for this line should be in the form $y = (-3)\, x + c$ .

The value of constant $c$ could be found using the other piece of information: the point $(3,\, 1)$ is in this line. In other words, the solution $\text{$x = 3$ and $y = 1$}$ should satisfy the equation $y = (-3)\, x + c$ .