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Masteriza [31]
3 years ago
14

Find the equation of the straight line passing through the point (3,5) which is perpendicular to the line y=3x+2

Mathematics
2 answers:
ohaa [14]3 years ago
5 0

Answer:

y=-1/3x+6 .Hope this helps

dedylja [7]3 years ago
3 0

Answer:

3y = -x + 18

Step-by-step explanation:

Given the equation y = 3x + 2;

By comparison with the general equation

y = mx + C ; where m is the slope

We see that m = 3

Now for a perpendicular line and it's slope is -1/m = -1/3 and let it be M2

But the new slope cuts across points (3,5) .

It means M2 = y - 5/ x-3

-1/3 = y-5/ x-3

-1(x-3) = 3(y-5)

-x +3 = 3y -15

3y = -x + 18

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To prove ∆LMN ≅ ∆PQR by SSS you need _______________ and<br> ______________ and ______________
Elis [28]

Given:

To prove ∆LMN ≅ ∆PQR by SSS you need _____________ and

_______________ and ______________.

To find:

The missing values.

Solution:

If ∆LMN ≅ ∆PQR by SSS, then all sides of ∆LMN are congruent to corresponding sides of ∆PQR.

LM\cong PQ

MN\cong QR

LN\cong PR

Therefore, the missing values are LM\cong PQ, MN\cong QR,LN\cong PR.

6 0
3 years ago
PLEASEE HELP!!
Alex777 [14]

Answer:

<h2>A)t=6.7</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • quadratic equation
  • quadratic equation word problems
  • solving quadratic
<h3>given:</h3>

h(t) = -4t² + 12t + 100

<h3>to solve:</h3>

t

<h3>tips and formulas:</h3>
  • <u>the</u><u> </u><u>Ball</u><u> </u><u>will</u><u> </u><u>hit </u><u>the</u><u> ground</u><u> </u><u>when</u><u> </u><u>the</u><u> height</u><u> is</u><u> </u><u>0</u>
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<h3>let's solve: </h3>

step - 1 :  \: define

- 4 {t}^{2}  + 12t + 100 = 0

step - 2 :  \\ divide \: both \: sides \: by \:  - 4

{t}^{2}  - 3t - 25 = 0

step - 3 :  \\ solve \: the \: quadratic

formula :  \\ x =  \frac{ - b± \sqrt{ {b}^{2} - 4ac }  }{2a}

define \: a ,b \: and \: c \\ which \: are \: 1, - 3 \: and \:  - 25 \: respectively

t =  \frac{ - ( - 3)± \sqrt{ {( - 3)}^{2} - 4.1. - 25 }  }{2.1}

t =  \frac{  3± \sqrt{ 9    + 100}  }{2}

t = \frac{3 +  \sqrt{ 109 } }{2}

t =  \frac{3  -  \sqrt{ 109 } }{2}

t = 6.7 \\ t =  - 3.7

as \: we \: know \: time \: cannot \: be \: negative

\huge \therefore \: t = 6.7

5 0
3 years ago
Please Help!!!!<br><br> A) 0<br><br> B) 1<br><br> C) 2<br><br> D) 5
mario62 [17]

B, that is where the line crosses the x axis

3 0
3 years ago
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Evaluate the function at x = –2.
MrRissso [65]
Y=3
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8 0
3 years ago
Given the equation y − 3 = 1/2 (x + 6) in point-slope form, identify the equation of the same line in standard form. )
Doss [256]

Answer:

a: x − 2y = −12

Step-by-step explanation:

the standard form of a line is is usually given as Ax + By = C, so just by deduction you can tell that the correct answer is a.

If you want to do the procedure it would be:

y − 3 = 1/2 (x + 6)

y − 3 = 1/2 x + 3

y - 1/2 x = 3 + 3

y - 1/2 x = 6

(y - 1/2 x = 6) * 2 to get rid of the fraction

2y - x = 12  rearrenge the terms

x - 2y = -12

4 0
3 years ago
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