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Anni [7]
3 years ago
11

Henry is standing on a catamaran at an elevation of 10 1010 feet relative to sea level. His friend Thomas is scuba diving at an

elevation of − 12 1 2 −12 2 1 ​ minus, 12, start fraction, 1, divided by, 2, end fraction feet relative to sea level. Which friend has greater elevation? Choose 1 answer: Choose 1 answer: (Choice A) A Henry (Choice B) B Thomas Which friend is farther from sea level? Choose 1 answer: Choose 1 answer: (Choice A) A Henry (Choice B) B Thomas
Mathematics
1 answer:
mario62 [17]3 years ago
6 0

Answer:

A.) Henry

B.) Thomas

Step-by-step explanation:

Given the following :

Henry's elevation = 10feets relative to sea level

Thomas elevation = -12 1/2 that is (-25/2) feet relative to sea level

Person with greater elevation:

Elevation can be described as height, in this case, the sea level used as the reference point. Therefore, a positive distance denotes an elevation above the reference point (which is the sea level). Therefore, Henry has a greater elevation of 10 feet( a distance above 0).

B) Who is farther from sea level:

This can be calculated by comparing the absolute distance between the elevation of both Henry and Thomas relative to the reference point(sea level)

Take reference point as 0

Absolute distances relative to sea level:

Henry's distance | 10 - 0 | = 10

Thomas's distance | -(25/2)- 0 | = 12 1/2

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hram777 [196]

Jeremiah got $65 on birthday and spent some money on 3 video games and was left with $14.

He purchased 3 video games.

Let the cost one one video game be v.

The cost of each video game is same

So the cost of 3 video games is 3v.

Also he is left with $14 after paying for three games.

Hence

3v + 14 = 65

Subtracting 14 from both sides

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v = 51/3

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Hence the cost of each video game is $17

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3 years ago
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If the measure of DEF is 65 what is the measure of DE. PLEASE HELP FAST
Wittaler [7]

EF is tangent to the circle we'll assume; otherwise there's no progress.


Call the center C. ECD is isosceles, formed from two radii and the chord.


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CED = 90 - 65 = 25 degrees


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That's the measure of arc DE as well:


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For a project in his Geometry class, Mamadou uses a mirror on the ground to measure the height of his school's football goalpost
andreev551 [17]

Answer:

Height of the goalpost is 9.25 m.

Step-by-step explanation:

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As we can see in the picture attached, both the angles (θ) are equal.

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ED = \frac{1.75\times 13.75}{2.6}

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