Answer:
The composition of the stars
Explanation:
Q = recessive allele frequency = 0.3, and thus in H-W equilibrium there are ONLY two alleles, q (recessive) and
p (dominant). Therefore all of the p and q present for this gene in a population must account for 100% of this gene's alleles. And 100% = 1.00.
So p, the dominant allele frequency, must be equal to 1 - q --> p = 1 - q
p = 1 - 0.3 = 0.7.
Since heterozygotes are a combination of the p and q, we must again look at the frequencies of each genotype: p + q = 1, then (p+q)^2 = 1^2
So multiplying out (p+q)(p+q) = 1, we get: p^2+2pq+q^2 = 1 (all genotypes), where p^2 = frequency of homozygous dominant individuals, 2pq = frequency of heterozygous individuals, and q^2 = frequency of homozygous recessive individuals.
Therefore if the population is in H-W equilibrium, then the expected frequency of heterozygous individuals = 2pq = 2(0.7)(0.3)
2pq = 2(0.21) = 0.42, or 42% of the population.
Hope that helps you to understand how to solve population genetics problems!
Organisms eat plants, which is comprised of carbohydrates; those carbohydrates come from Carbon<span> dioxide in the atmosphere. Thus, an abiotic factor (</span>carbon<span>dioxide) helps create a </span>biotic<span> factor (the plants made out of carbohydrates).</span>
If not my mistaken this would be the answer
The cell will change the concentration of water within the cell to match the concentration of water outside the cell.
<span>This is continuous aerobic activity. While regular aerobic activity can incorporate rest periods, this style of activity does not. Activities such as walking, slow jogging, stair climbing, and swimming can all fit this definition, because they can be done without rest for long periods.</span>
