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alexira [117]
3 years ago
6

Select one: A. Supplementary B. Vertical C. Complementary D. Acute

Mathematics
1 answer:
Rom4ik [11]3 years ago
5 0

Shouldnt there be a picture or something?

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What is the area of the trapezoid
irga5000 [103]

The equation for a trapezoid is A = a+b all over 2 times h

So, you would simply substitute.

A=15

B=12

H=8

15+12/2 (8)=

27/2 (8)=

13.5 (8)=

108.

6 0
3 years ago
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What is the formula for the area A of a trapezoid with parallel sides of length B and D, nonparallel sides of length A and C and
loris [4]

Answer:

(B) \dfrac12H (B+D)

Step-by-step explanation:

\text{Area of a trapezoid }= \dfrac12 ($Sum of the parallel sides) \times $Height\\Parallel Sides = B and D\\Height =H\\Therefore:\\\text{Area of the trapezoid }= \dfrac12 (B+D) H

The correct option is B.

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4 years ago
A cylinder and sphere have the same height. If the sphere has a volume of 361 cubic units, what is the height of the cylinder?
dalvyx [7]

Answer:

Sa = 36 circumference per meter square

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3 years ago
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You work for a company that produces custom picture frames. A new customer needs to frame a piece of rectangular artwork with di
miskamm [114]

Answer:

None of the choices are correct.

Step-by-step explanation:

Let x be the width of the frame,

The framed art cannot me more than 320 square inches

(11 + 2x) \times (15+2x) \leq 320

(165 +30x +22x +4x^2 ) \leq 320

4x^2+52x + 165 \leq 320

4x^2 +52x + 165-320 \leq 0

4x^2 +52x - 155\leq 0

By using the quadratic formula

x = \frac{-b\pm \sqrt{(b^2-4ac)}}{2a}

x = \frac{-52\pm \sqrt{(52^2-4(4)(-155))}}{2(4)}

x = \frac{-52\pm \sqrt{(2704+2480)}}{2(4)}

x = \frac{-52\pm \sqrt{(5184)}}{2(4)}

x = \frac{-52\pm 72}{2(4)}

x = \frac{20}{8}

x= \frac{5}{2}

x = 2.5

Frame must not be more than 2.5 inches wide.

4 0
3 years ago
Math question I need help with it please help me !
never [62]

Answer:

96 degrees

Step-by-step explanation:

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3 years ago
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