2x + 1
You can find that by switching the signs in the second set of parenthesis and then adding.
Answer:
Step-by-step explanation:
Our equations are

Let us understand the term Discriminant of a quadratic equation and its properties
Discriminant is denoted by D and its formula is

Where
a= the coefficient of the 
b= the coefficient of 
c = constant term
Properties of D: If D
i) D=0 , One real root
ii) D>0 , Two real roots
iii) D<0 , no real root
Hence in the given quadratic equations , we will find the values of D Discriminant and evaluate our answer accordingly .
Let us start with

Hence we have two real roots for this equation.


Hence we do not have any real root for this quadratic

Hence D>0 and thus we have two real roots for this equation.

Hence we have one real root to this quadratic equation.
<span>SAS
You've been given that AC = BC. So that's the first side or S of the proof. Then you've been given â 3 = â 4, which is the angle. And finally, CM = CM, which is the second S. So you have AC=BC, and â 3 = â 4, and finally CM = CM. So SAS can be used to prove that triangle ACM is congruent to triangle BCM.</span>
Answer:
32
Step-by-step explanation:
Multiply both sides by 8.
y/8 = 4
y/8 × 8 = 4 × 8
y = 32