The path of a model rocket can be represented by the equation h(t)=-t2+15t+16, where h(t) is the height, in feet, of the rocket
at any given time, t. what is the height of the model rocket after 3 seconds from launch?
2 answers:
The height is 52 feet.
Using t=3, we have:
-3² + 15(3) + 16 = -9 + 45 + 16 = 52
we are given

where h(t) is height in feet
t is time in seconds
now, we can plug t=3 and find height



so,
the height of the model rocket after 3 seconds from launch is 52 feet.......Answer
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