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We can calculate dy/dx using implicit differentiation:
xy + y² = 6
Differentiate both sides. Remember to use the Product Rule for the "xy" term:
(1)y + x(dy/dx) + 2y(dy/dx) = 0
Move y to the opposite side:
x(dy/dx) + 2y(dy/dx) = -y
Factor out dy/dx:
dy/dx(x + 2y) = -y
Divide both sides by x + 2y:
dy/dx = -y/x + 2y
We need both x and y to find dy/dx, so plug in the given value of x into the original equation:
-1(y) + y² = 6
-y + y² = 6
y² - y - 6 = 0
(y - 3)(y + 2) = 0
Thus, y = -2 and 3.
We can calculate dy/dx at each point:
At y = -2: dy/dx = -(-2) / -1+ 2(-2) = -2/5.
At y = 3: dy/dx = -(3) / -1 + 2(3) = -3/5.
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If Point C and D are equidistant from point A, it means that AC and AD are of the same length. AC = AD
AC = AD (S) (<span>Points C and D are equidistant from point A)
</span>AE = AE (S) (The two triangle shared the same side)
∠CAE = ∠EAD (A) (This angle is between the two sides that we just proved to be equal)
By SAS,
ΔEAD ≡ ΔEAC
Answer:
y = 1/2 (2)x
Step-by-step explanation:
Using the equation y = abx , substitute both of your given points into that equation.
2 = ab2 and 4 = ab3 Solve each equation for a.
2⁄b2 and 4⁄b3 = a Therefore, 2⁄b2 = 4⁄b3
Cross multiply: 2b3 = 4b2 Divide both sides by b2
2b = 4 a = 2/4 = 1/2
b = 2
Answer:
5x + 32 < 50
Step-by-step explanation:
On a particular airline, bags checked in must weigh less than 50 pounds. Betty packed 32 pounds of clothes and five gifts that weigh the same amount.
If each gift weighs w pounds, then the weight of five gifts will be 5w pounds and an additional 32 pounds of clothes will make it total (32 + 5w) pounds.
Now, this total weight has to be less than 50 pounds.
Therefore, the inequality equation that can be used to find the possible weight of each gift, w is
5x + 32 < 50 (Answer)