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ikadub [295]
3 years ago
8

(1/3) to the power of 4

Mathematics
2 answers:
aalyn [17]3 years ago
7 0

Answer:

1/84

Step-by-step explanation:

This was a very complicated problem but the only way that I could solve this was by using a calculator.

Kaylis [27]3 years ago
3 0

Answer:

1/84

Step-by-step explanation:

You might be interested in
How do you do this question?
Molodets [167]

Answer:

C. y₂ = (1 + (t/n))²

Step-by-step explanation:

yₙ₊₁ = yₙ + Δt F(tₙ, yₙ)

yₙ₊₁ = yₙ + Δt yₙ

yₙ₊₁ = yₙ + (t/n) yₙ

When n=0:

y₁ = y₀ + (t/n) y₀

y₁ = 1 + (t/n)

When n=1:

y₂ = y₁ + (t/n) y₁

y₂ = 1 + (t/n) + (t/n) (1 + (t/n))

y₂ = 1 + (t/n) + (t/n) + (t/n)²

y₂ = 1 + 2(t/n) + (t/n)²

y₂ = (1 + (t/n))²

4 0
3 years ago
PLEASE HELP! I'm struggling on questions like this one. If you can please help on other questions but that's up to you! I will g
Setler79 [48]

Answer:

y=3/2x+3

Step-by-step explanation:

the line hits the y-axis at 3 so b=3 and the change in y is up 3 and the change in x is to the right 2 so the change in y over the change in x is 3/2

7 0
3 years ago
What is the ratio for sine
Sphinxa [80]

Answer:

Blank 1: opposite

Blank 2: adjacent

Blank 3: opposite

Blank 4: adjacent

Step-by-step explanation:

There is a trigonometric acronym for this which is:

Soh Cah Toa

Soh means that sine is opposite over hypotenuse.

Cah means that cosine is adjacent over hypotenuse.

Toa means that tangent is opposite over adjacent.

Let me actually write these out as fractions:

sine is \frac{\text{opposite}}{\text{hypotenuse}}

cosine is \frac{\text{adjacent}}{\text{hypotenuse}}

tangent is \frac{\text{opposite}}{\text{adjacent}}

Blank 1: opposite

Blank 2: adjacent

Blank 3: opposite

Blank 4: adjacent

4 0
2 years ago
Find the product.
Inga [223]
(2p + 7)(3p-9)
2p x 3p= 6p^2
2p x -9= -18p
7 x 3p=21p
7 x -9=-63
6p^2 - 18p + 21p - 63
6p^2 + 3p -63 is the answer.

6 0
3 years ago
Read 2 more answers
I want the answers because i don't know how to do it
Andrew [12]
Question one is y( Insert sign) -9
6 0
3 years ago
Read 2 more answers
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