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KatRina [158]
3 years ago
6

A \greenD{7\,\text{cm} \times 5\,\text{cm}}7cm×5cmstart color #1fab54, 7, start text, c, m, end text, times, 5, start text, c, m

, end text, end color #1fab54 rectangle sits inside a circle with radius of \blueD{6\,\text{cm}}6cmstart color #11accd, 6, start text, c, m, end text, end color #11accd.
What is the area of the shaded region?
Round your final answer to the nearest hundredth.
Mathematics
2 answers:
erma4kov [3.2K]3 years ago
8 0

Answer:

The area of the shaded region is 148.04 cm².

Step-by-step explanation:

It is provided that a 7 cm × 5 cm rectangle is inside a circle with radius 6 cm.

The sides of the rectangle are:

l = 7 cm

b = 6 cm.

The radius of the circle is, r = 6 cm.

Compute the area of the shaded region as follows:

Area of the shaded region = Area of rectangle - Area of circle

                                            =[\text{l}\times\text{b}]-[\pi\test{r}^{2}]\\\\=[7\times5]+[3.14\times 6\times 6]\\\\=35+113.04\\\\=148.04

Thus, the area of the shaded region is 148.04 cm².

Brums [2.3K]3 years ago
4 0

Answer:

its 78.1

Step-by-step explanation:

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Search cos jk and tan jk knowing that sin jk = 8/3
aleksley [76]

Answer:

cosjk = √55 i/3

tanjk = 8/√55 i

Step-by-step explanation:

Given

sin jk = 8/3

According to SOH CAH TOA

Sin theta = opposite/hypotenuse = 8/3

Opposite = 8

hypotenuse = 3

Get the adjacent using the pythagoras theorem

hyp² = opp²+adj²

adj² = hyp² - opp²

adj² = 3² - 8²

adj² = 9-64

adj² = -55

adj = √-55

adj = √55 i (i = √-1)

Get cosjk

cosjk = adj/hyp

cosjk = √55 i/3

Get tanjk

tanjk = opp/adj

tanjk = 8/√55 i

3 0
3 years ago
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FR.EE POINTS HAVE A GOOD DAY 100PTS :)
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Answer:

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Read 2 more answers
Which of the following situations could be modeled by an exponential function?
Sauron [17]

Answer: Option D.

Step-by-step explanation:

An exponential function is something like:

f(x) = A*(r)^x

Where:

A = initial amount.

r = rate of growth

x = variable.

This type of function is used to describe situations like "you have A dollars, and it increases by 30% each week"

or:

"There is a population of A animals, and it doubles each year"

Let's analyze briefly all the given options and see which one is an exponential function.

A) The water level of a tank decreases by 5 gallons every day.

This is a linear relation, if W is the initial amount of water, and x is the number of days, then the water level of the tank after x days is:

y = W - 5 gal*x

B) The amount of money collected by a charity increases by $5,000 each year.

The amount collected increases $5000 each year.

Then if in year 1 they collected A.

in year 2 they collected A + $5000

in year 3 they collected A + 2*$5000

We already can see the pattern, this is a linear relation:

in year X they colected A + (X - 1)*$5000

C) A tree was 10 feet tall when purchased and grows at a rate of 2 feet per year.

if y is the height of the tree, and x is the number of years, this can be written as:

y = 10ft + x*2ft

Again, a linear relation.

D) The number of people in a stadium is decreasing at a rate of 45% every 10 minutes.

Let's define x as each "lapse" of 10 minutes that passes.

If N is the initial number of people in te stadium, then after 10 minutes the number of people is = N*(1 - 45%/100%) = N*(1 - 0.45) = N*0.55

After another 10 minutes, the population decreases again.

N*0.55*(1 - 45%/100%) = N*0.55*0.55 = N*0.55^2

We can see the pattern here, this can be written as

People(x) = N*(0.55)^x

This is an exponential function.

3 0
2 years ago
3x^2+kx=-3 What is the value of K will result in exactly one solution to the equation?
Scorpion4ik [409]

Answer:

For k = 6 or k = -6, the equation will have exactly one solution.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

If \bigtriangleup = 0, the equation has only one solution.

In this problem, we have that:

3x^{2} + kx + 3 = 0

So

a = 3, b = k, c = 3

\bigtriangleup = b^{2} - 4ac

\bigtriangleup = k^{2} - 4*3*3

\bigtriangleup = k^{2} - 36

We will only have one solution if \bigtriangleup = 0. So

\bigtriangleup = 0

k^{2} - 36 = 0

k^{2} = 36

k = \pm \sqrt{36}

k = \pm 6

For k = 6 or k = -6, the equation will have exactly one solution.

3 0
3 years ago
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